Hermite Polynomial Recurrence Question

Click For Summary
SUMMARY

The discussion centers on deriving the expression for \( y^{2}H(y) \) using Hermite polynomials. The user successfully identifies the relation \( yH(y) = \frac{1}{2}H_{n+1}(y) + nH_{n-1}(y) \) but seeks guidance on extending this to \( y^{2}H(y) \). The recommended approach is to multiply both sides of the known relation by \( y \) and then expand the right-hand side to achieve the desired expression.

PREREQUISITES
  • Understanding of Hermite polynomials and their properties
  • Familiarity with polynomial recurrence relations
  • Basic knowledge of mathematical expansion techniques
  • Experience with mathematical notation and manipulation
NEXT STEPS
  • Research the properties of Hermite polynomials, specifically their recurrence relations
  • Learn about polynomial multiplication and expansion techniques
  • Explore advanced topics in orthogonal polynomials
  • Study applications of Hermite polynomials in physics and engineering
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on polynomial theory and recurrence relations, will benefit from this discussion.

timman_24
Messages
52
Reaction score
0

Homework Statement


I need to find an expression for:
[itex]y^{2}H(y)[/itex]

I know how to find:
[itex]yH(y)[/itex]
with:
[itex]yH(y)=\frac{1}{2}H_{n+1}(y)+nH_{n-1}(y)[/itex]

I looked through the miscellaneous relations but nothing stuck out to me. Can someone give me some guidance on how to go about finding a relation? I assume I do not simply multiply both sides by y!

Thanks
 
Physics news on Phys.org
Multiply both sides by y, then expand out the righthand side.
 

Similar threads

Replies
24
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K