Can Hermitian Operators Commute if Their Commutator is Also Hermitian?

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The discussion revolves around proving that if A, B, and C are Hermitian operators and their commutator [A, B] equals C, then C must be zero. Participants explore the properties of Hermitian operators, noting that A, B, and C are equal to their adjoints. The key point is that by expanding the commutator and applying the property of Hermitian operators, it can be shown that C' equals -C. This leads to the conclusion that C must be zero, as the only solution to C = -C is C = 0. The discussion emphasizes the algebraic manipulation of the operators and their properties to arrive at this conclusion.
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Homework Statement


[A,B] = C and operators A,B,C are all hermitian show that C=0


Homework Equations





The Attempt at a Solution



Since it is given that all operators are hermitian I know that A=A' B=B' and C=C' so i expanded it out to
AB-BA=C
A'B'-B'A'=C
(BA)' - (AB)'=C


I'm not real sure where I am supposed to go or what properties of hermitian operators I am supposed to used to show that AB=BA..any help would be appreciated thank
 
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Going back to AB-BA=C, what is C' equal to? How does it compare to what you derived so far?
 
vela said:
Going back to AB-BA=C, what is C' equal to? How does it compare to what you derived so far?

So would I just treat C and C' as separate equations, equate them and show that it equals zero?

ie:

C'=AB-BA
C=(BA)'-(AB)' and just use the fact that all the operators are hermitian?
 
Not exactly. You have C=AB-BA, so C' = (AB-BA)'. With a little algebra, you should be able to show that C' = -C.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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