solakis1
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Given A>0, find a B>0 such that :
for all x,y,a,b : if 0<x<1,0<y<1,0<a<1,0<b<1,and |x-a|<B,|y-b|<B,then $$|x^2y-a^2b|<A$$
for all x,y,a,b : if 0<x<1,0<y<1,0<a<1,0<b<1,and |x-a|<B,|y-b|<B,then $$|x^2y-a^2b|<A$$