B High voltage batteries and charge distribution

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Touching a metal spoon to the anode of a high voltage battery will result in the spoon accumulating charges based on the potential difference between the anode and the ground. If the spoon is held and not insulated, it is assumed to be at zero potential relative to the ground. The anode's potential relative to the ground is crucial; if it is at a higher voltage than the spoon, positive charges will flow to the spoon, resulting in a loss of electrons. Conversely, if the anode is at a lower potential, negative charges will accumulate on the spoon. The specific outcome depends on the voltage levels of the battery components and their relation to ground.
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Homework Statement: If we touch a metal spoon on the anode of high voltage battery. Then what charges will accumulate on the spoon, positive or negative?
Relevant Equations: No such a equation

I think, negative charges because electrode equilibrium in the anode says some electrones acculilate on the metal bar of anode. So we connect metal spoon to anode, it will also get electrons from anode metal bar and distribute those electrons such a way that spoon get the same potential as the anode

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Is this a homework question?
The sign of charge going to the spoon will depend on the potential difference between the battery anode and the ground. I assume that the spoon will be at zero potential relative to the ground if you are holding it and not standing on an insulator. But you have to specify more about the situation than you have done.
From your diagram, all you can say is that the anode will be at a positive potential relative to the cathode. You cannot rely on where the mean potential (relative to ground) of the battery sits - it could be anywhere, depending on what you did to it before it was 'up in the air. If you left the cathode at +100V relative to earth, the anode would be at 112V and positive charge would go to the spoon (i.e. electrons flow off it) until the anode potential was 0V. The cathode would them be at -12V.
 
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