- #1
ayans2495
- 58
- 2
- Homework Statement
- What is the mass of the object?
- Relevant Equations
- F = ma
Hiking the Appalachian Trail: A Beginner's Guide
- Thread starter ayans2495
- Start date
AI Thread Summary
The discussion revolves around the concept of net force in relation to weight and mass calculations, specifically in the context of drag force. It highlights that a horizontal function does not always indicate zero net force, but in this case, it does due to the constant drag force. The conversation also references Newton's second law to clarify this relationship. Additionally, there is a mention of an unanswered question, suggesting a need for further engagement on the topic. Understanding the nuances of force dynamics is essential for accurate problem-solving in physics.
- #2
ayans2495
- 58
- 2
My answer: Horizontal function implies zero net force. Therefore, weight is 160 N. Thus, mass is 16 kg such that the acceleration due to gravity is 9.8 N/kg. Am I right?
- #3
Delta2
Homework Helper
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Your answers are correct but your reasoning is not entirely correct or it is incomplete I would say. The part of the graph where it becomes horizontal doesn't necessarily imply that the net force is zero, however it is implying it in this specific case of drag force being constant. Why? What's the special thing about drag force and how this combined with Newton's second law implies that the net force is zero.
- #4
Delta2
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You haven't answer question 25 btw but ok its fairly easy after answering the first two questions.
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question.
Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point?
Lets call the point which connects the string and rod as P.
Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
F1=(5000+200)g=5200*10=52000N --> F2=(5000+100)g=5100*10=51000N ?
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