Hiking the Appalachian Trail: A Beginner's Guide

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SUMMARY

The discussion centers on the physics of horizontal motion and drag force in the context of hiking the Appalachian Trail. It establishes that while a horizontal function indicates zero net force, this is specifically true when drag force remains constant. The conversation highlights the importance of understanding Newton's second law in analyzing forces acting on a hiker. Additionally, it points out an oversight regarding a specific question that remains unanswered, emphasizing the need for thoroughness in problem-solving.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic knowledge of drag force and its implications
  • Familiarity with force diagrams and their interpretations
  • Ability to analyze motion in a physics context
NEXT STEPS
  • Study the principles of drag force and its effects on motion
  • Learn how to apply Newton's second law to various scenarios
  • Explore force diagrams and their role in understanding net forces
  • Review common physics problems related to horizontal motion
USEFUL FOR

Physics students, educators, and outdoor enthusiasts interested in the mechanics of hiking and the forces involved in outdoor activities.

ayans2495
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Homework Statement
What is the mass of the object?
Relevant Equations
F = ma
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My answer: Horizontal function implies zero net force. Therefore, weight is 160 N. Thus, mass is 16 kg such that the acceleration due to gravity is 9.8 N/kg. Am I right?
 
Your answers are correct but your reasoning is not entirely correct or it is incomplete I would say. The part of the graph where it becomes horizontal doesn't necessarily imply that the net force is zero, however it is implying it in this specific case of drag force being constant. Why? What's the special thing about drag force and how this combined with Newton's second law implies that the net force is zero.
 
You haven't answer question 25 btw but ok its fairly easy after answering the first two questions.
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
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