- #1
ayans2495
- 58
- 2
- Homework Statement
- What is the mass of the object?
- Relevant Equations
- F = ma
Hiking the Appalachian Trail: A Beginner's Guide
- Thread starter ayans2495
- Start date
AI Thread Summary
The discussion revolves around the concept of net force in relation to weight and mass calculations, specifically in the context of drag force. It highlights that a horizontal function does not always indicate zero net force, but in this case, it does due to the constant drag force. The conversation also references Newton's second law to clarify this relationship. Additionally, there is a mention of an unanswered question, suggesting a need for further engagement on the topic. Understanding the nuances of force dynamics is essential for accurate problem-solving in physics.
- #2
ayans2495
- 58
- 2
My answer: Horizontal function implies zero net force. Therefore, weight is 160 N. Thus, mass is 16 kg such that the acceleration due to gravity is 9.8 N/kg. Am I right?
- #3
Delta2
Homework Helper
- 6,002
- 2,628
Your answers are correct but your reasoning is not entirely correct or it is incomplete I would say. The part of the graph where it becomes horizontal doesn't necessarily imply that the net force is zero, however it is implying it in this specific case of drag force being constant. Why? What's the special thing about drag force and how this combined with Newton's second law implies that the net force is zero.
- #4
Delta2
Homework Helper
- 6,002
- 2,628
You haven't answer question 25 btw but ok its fairly easy after answering the first two questions.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
Here we know that if block B is going to move up or just be at the verge of moving up
##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ##
Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Similar threads
Hot Threads
-
Torque biomechanics
- Started by Naucus
- Replies: 6
- Introductory Physics Homework Help
-
Work Done in slowly pulling a thread
- Started by Bling Fizikst
- Replies: 28
- Introductory Physics Homework Help
Recent Insights
-
Insights Why Entangled Photon-Polarization Qubits Violate Bell’s Inequality
- Started by Greg Bernhardt
- Replies: 2
- Quantum Physics
-
Insights Quantum Entanglement is a Kinematic Fact, not a Dynamical Effect
- Started by Greg Bernhardt
- Replies: 11
- Quantum Physics
-
Insights What Exactly is Dirac’s Delta Function? - Insight
- Started by Greg Bernhardt
- Replies: 3
- General Math
-
Insights Relativator (Circular Slide-Rule): Simulated with Desmos - Insight
- Started by Greg Bernhardt
- Replies: 1
- Special and General Relativity
-
Insights Fixing Things Which Can Go Wrong With Complex Numbers
- Started by PAllen
- Replies: 7
- General Math
-
Insights Fermat's Last Theorem
- Started by fresh_42
- Replies: 105
- General Math