- #1
ayans2495
- 58
- 2
- Homework Statement
- What is the mass of the object?
- Relevant Equations
- F = ma
Hiking the Appalachian Trail: A Beginner's Guide
- Thread starter ayans2495
- Start date
AI Thread Summary
The discussion revolves around the concept of net force in relation to weight and mass calculations, specifically in the context of drag force. It highlights that a horizontal function does not always indicate zero net force, but in this case, it does due to the constant drag force. The conversation also references Newton's second law to clarify this relationship. Additionally, there is a mention of an unanswered question, suggesting a need for further engagement on the topic. Understanding the nuances of force dynamics is essential for accurate problem-solving in physics.
- #2
ayans2495
- 58
- 2
My answer: Horizontal function implies zero net force. Therefore, weight is 160 N. Thus, mass is 16 kg such that the acceleration due to gravity is 9.8 N/kg. Am I right?
- #3
Delta2
Homework Helper
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Your answers are correct but your reasoning is not entirely correct or it is incomplete I would say. The part of the graph where it becomes horizontal doesn't necessarily imply that the net force is zero, however it is implying it in this specific case of drag force being constant. Why? What's the special thing about drag force and how this combined with Newton's second law implies that the net force is zero.
- #4
Delta2
Homework Helper
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You haven't answer question 25 btw but ok its fairly easy after answering the first two questions.
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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