Hinged beam suspended at an angle

[rickbusiness]

Homework Statement

A 35.8 kg beam is attached to a wall with a hinge and its far end is supported by a cable. The angle between the beam and the cable is 90°. If the beam is inclined at an angle of theta=17.8° with respect to horizontal, what is the horizontal component of the force exerted by the hinge on the beam? (Use the 'to the right' as + for the horizontal direction.)

What is the magnitude of the force that the beam exerts on the hinge?

heres a picture: http://tinypic.com/r/141v7o6/6

Homework Equations

f=ma
t=Fr

The Attempt at a Solution

forces in the x dricection= 0
forces in the y direction= 0
net torque = 0

I think the tension can be found by L/2mgcos(theta)=LT
T=1/2mgcos(theta)

so the x component of the tension= x component of the hinge on the beam

Fx=Tsin(theta)The system is in equilibrium
Im unsure about how to approach this question because the beam is on an angle. An explanation with a worked solution would be very very much appreciated.

 

[rickbusiness]

nevermind, figured it out. for anyone doing a similar problem here's my sol'n

Fxhinge=Tsin(theta)
Fy=0=Tcos(theta)-mg+Fyhinge
Fyhinge=mg-Tcos(theta)

Fxhinge squared + Fyhinge squared = F hinge squared