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Hinged beam suspended at an angle

  1. Nov 20, 2012 #1
    1. The problem statement, all variables and given/known data
    A 35.8 kg beam is attached to a wall with a hinge and its far end is supported by a cable. The angle between the beam and the cable is 90°. If the beam is inclined at an angle of theta=17.8° with respect to horizontal, what is the horizontal component of the force exerted by the hinge on the beam? (Use the 'to the right' as + for the horizontal direction.)

    What is the magnitude of the force that the beam exerts on the hinge?

    heres a picture: http://tinypic.com/r/141v7o6/6

    2. Relevant equations

    f=ma
    t=Fr

    3. The attempt at a solution

    forces in the x dricection= 0
    forces in the y direction= 0
    net torque = 0

    I think the tension can be found by L/2mgcos(theta)=LT
    T=1/2mgcos(theta)

    so the x component of the tension= x component of the hinge on the beam

    Fx=Tsin(theta)


    The system is in equilibrium
    Im unsure about how to approach this question because the beam is on an angle. An explanation with a worked solution would be very very much appreciated.
     
    Last edited: Nov 20, 2012
  2. jcsd
  3. Nov 20, 2012 #2
    nevermind, figured it out. for anyone doing a similar problem heres my sol'n

    Fxhinge=Tsin(theta)
    Fy=0=Tcos(theta)-mg+Fyhinge
    Fyhinge=mg-Tcos(theta)

    Fxhinge squared + Fyhinge squared = F hinge squared
     
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