Hmmmm how to find the taylor series based @ b for this function?

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Homework Help Overview

The discussion revolves around finding the Taylor series for the function 1/(4x-5) - z/(3x-2) centered at 0. Participants are exploring how to apply known Taylor series expansions, such as those for e^x, sin x, or 1/(1-x), to this problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the relationship between the function and known Taylor series. There is confusion regarding the presence of the variable z and whether the function involves two variables. Some suggest using the expansion of inverse linear functions as a power series.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on how to approach the problem. Some guidance has been offered regarding the use of known series expansions, but there is still uncertainty about the setup and the role of z in the context of the Taylor series.

Contextual Notes

There is a lack of clarity regarding the function's variables and the original poster's understanding of Taylor series, which may be affecting the discussion. Participants are also navigating the challenge of refreshing their memory on the topic.

myusernameis
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Homework Statement



1/(4x-5) - z/(3x-2) based @ 0, answers are in those z things.. sigma

Homework Equations


i think we use sigma of e^x, but idk how...


The Attempt at a Solution


since tayor sereis of e^x is like 1/x, do i plug 4x-5 in?

thanks
 
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I really don't understand that. Is that a function of two variables, x and z?
 
Dick said:
I really don't understand that. Is that a function of two variables, x and z?

haha... no i don't know how "z" got in there... the question is asking us to find the taylor series by using like e^x, sin x, or 1/(1-x) taylor series...
idk if that's making sense ...
 
Then use things like 1/(1-x)=1+x+x^2+... You can expand inverse linear functions like 1/(ax+b) as a power series.
 
myusernameis said:
haha... no i don't know how "z" got in there... the question is asking us to find the taylor series by using like e^x, sin x, or 1/(1-x) taylor series...
idk if that's making sense ...

You didn't ask my opinion, but I'll give it to you anyway, for free. I think you're in a class that's way over your head. You don't seem to be able to tell us what the problem is, and I don't believe you have any idea what a Taylor's series is. Much of what you've written makes no sense ("sigma of e^x", "answers are in those z things ... sigma").

Mark
 
Mark44 said:
You didn't ask my opinion, but I'll give it to you anyway, for free. I think you're in a class that's way over your head.
Mark

haha :D you are kind of right... i learned this stuff but I'm trying to refresh my memory... and as for the "z things" i was just trying to be stupid...
thanks for the advice tho... and i do know what a taylor series is.. i think.
(is it to approximate another function at a point?)
i think that's what it is.edit: lol ", for free." XD
 
Last edited:
Dick said:
Then use things like 1/(1-x)=1+x+x^2+... You can expand inverse linear functions like 1/(ax+b) as a power series.

ahh thanks!
 

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