Holographic grating - can we calculate efficiency for each order?

[Turksen]

Hi,

I'm new to working with gratings. From using the basic grating eqn., I'm able to model the diffraction angles for each order with different angles of incidence upon the grating and I can calculate the dispersion given a broadband source with known minimum and maximum wavelength.

However, I'm unsure how the angle of incidence affects the power going into each order. I think the n=+1 order is usually the most efficient, although is there a dependence upon the incidence angle / diffraction angle for efficiency?

Thanks

 

[Andy Resnick]

Grating efficiency is a complex function of incident polarization and groove shape- I'm not sure there is a underlying analytic theory to start from. To get started, see chapter 9-

http://gratings.newport.com/library/handbook/handbook.asp

and

http://www.opticsinfobase.org/ao/abstract.cfm?uri=ao-16-10-2711

 

[Turksen]

Grating efficiency is a complex function of incident polarization and groove shape- I'm not sure there is a underlying analytic theory to start from. To get started, see chapter 9-

http://gratings.newport.com/library/handbook/handbook.asp

and

http://www.opticsinfobase.org/ao/abstract.cfm?uri=ao-16-10-2711

Thanks, I've seen the handbook already but will check out the paper.

Cheers!

 

[Khashishi]

In the case of some volume phase gratings I've seen, the shape of the grating only allows one order to exist. The higher orders have a larger than 90 degree diffraction angle and therefore don't exist. You might check out: R.E. Bell. Exploring a transmission grating spectrometer. RSI 75 10 (2004)