Homework: find right coset of a group

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Homework Help Overview

The problem involves a group G and its subgroup H, with the index [G:H] equal to 2. Participants are tasked with finding all the right and left cosets of H in G.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the existence of two distinct right cosets and question how to identify them. There is mention of selecting elements from G that are not in H to define the cosets. Some participants explore the implications of different choices for elements in G and their relation to the cosets.

Discussion Status

There is a productive exploration of the relationship between right and left cosets, with some participants confirming the identification of cosets. However, there is no explicit consensus on whether the identified cosets are sufficient or correct, as questions about their equality and implications are raised.

Contextual Notes

Participants are working under the constraint that the index of the subgroup is 2, which influences the number of cosets and their properties. There is also a focus on the definitions and relationships between right and left cosets.

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Homework Statement



Let G be a group, H is subgroup of G, and [G:H]=2
find all the right and left coset of H in G

Homework Equations



n/a

The Attempt at a Solution



(finding right coset)

so there exist 2 distinct right coset, but how to find the 2 right coset?

let a,b in G

so Ha and Hb are the right coset if Ha\capHb={}

then?
 
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Pick an a in G that is not in H. Then the right cosets are H and Ha, right?
 


yes, and is that the answer?

let a in G not in H

H and Ha are the right coset of H in G
H and aH are the left coset of H in G
is that correct and sufficient?

what if i do like this

let ab-1 in G not in H

Ha and Hb are the right coset of H in G
aH and bH are the left coset of H in G
it's the same thing right?
 


Same thing, yes. But I don't know that it really helps you in any way. I think the point is that there is only one right coset that is not equal to H and there is only one left coset that is is not equal to H. So they must be equal. Isn't that the point?
 


yea, haha, like you said, i wanted to show Hx=xH for all x in G, thank you very much,
 

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