Homework Help: Equations & Solutions

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Homework Help Overview

The discussion revolves around a physics problem involving pressure calculations in a cylinder with a piston. Participants are examining the relationship between force, area, and pressure, as well as the effects of atmospheric pressure and the weight of the piston on the overall system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the necessity of considering the weight of the piston and its impact on pressure calculations. There are attempts to clarify the relationship between force and pressure using the equation F=PA, and questions arise regarding the correct interpretation of pressure in the context of the problem.

Discussion Status

There is an ongoing exploration of the forces acting on the piston, with some participants providing guidance on how to approach the pressure calculations. Multiple interpretations of the problem are being discussed, particularly regarding the role of atmospheric pressure and the weight of the piston.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for solving the problem. The original poster has expressed difficulty in arriving at the correct answer, prompting further inquiry into the assumptions made in their calculations.

yecko
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Homework Statement


http://i.imgur.com/wSvUEU2.png
wSvUEU2.png


Homework Equations


(written in the photo)

The Attempt at a Solution


(written in the photo)
Thanks
 
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It all seems to be there, so I'm not sure what you are missing.

The area is clear from the 10cm cylinder. If you know the area then the pressure is clear from the force of gravity on the weight divided by the area (and + 1 atmosphere for the external pressure on the cylinder.) n is given, the Ts are given. What else do you need?
 
As Cutter Ketch noted, the pressure of the gas is not atmospheric pressure. The weight of the piston must be taken into account.
 
Do I really need to consider the weight of the piston? because it seems to be a constant factor... no change in the case...
Cutter Ketch said:
If you know the area then the pressure is clear from the force of gravity on the weight divided by the area (and + 1 atmosphere for the external pressure on the cylinder.)
do you mean "F=PA=mg" to be simple? however, what's going on with it?
 
Oh, I see. You aren't getting the right answer. So I take it the hand written answers are correct and the red is what you got?
 
Cutter Ketch said:
You aren't getting the right answer. So I take it the hand written answers are correct and the red is what you got?
Words in red are written by me
and the circle of the option is the right answer
i got c, while the right answer is a...
thanks
 
yecko said:
Do I really need to consider the weight of the piston? because it seems to be a constant factor... no change in the case...

do you mean "F=PA=mg" to be simple? however, what's going on with it?

You don't need it because it changes. You need it because you can't define the initial condition without it. Since h1 isn't given you have to figure it out. Your formula for h1 is correct, and in that formula is pressure. You need the absolute pressure to determine h1, and that pressure includes holding up the piston.
 
so you mean i should eliminate the factor for h1 first in order to find out the pressure if piston is not present?
how should i relate PV=nRT to force?
 
Your calculation in red is correct except for the value of the pressure P1. P1 does not equal atmospheric pressure.

To find the correct pressure, switch your attention to the piston and consider all the forces acting on the piston.
 
  • #10
TSny said:
P1 does not equal atmospheric pressure
by F=PA=mg, P should be equal to mg/A=50*9.81/(0.05^2*pi)=62452Pa?
I still can't get the written answer...
 
  • #11
yecko said:
by F=PA=mg, P should be equal to mg/A=50*9.81/(0.02^2*pi)=62452Pa?
That's not the pressure of the gas inside the container.

How many forces act on the piston? Describe each force.
 
  • #12
TSny said:
Describe each force
weight and pressure by gas
am i right?
 
  • #13
yecko said:
weight and pressure by gas
am i right?
There's one more force. The problem states that the top of the piston is "open to the air".
 
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  • #14
pressure of the air?
mg+P(a)A=P(g)A
P(g)=163689Pa ?
 
  • #15
That's it. Good!
 
  • #17
I'm off to bed. :sleep: Will check back tomorrow.
 
  • #18
Thanks you~
Then I will come back here at night of my local time~
because i am going to have exam tomorrow, hope all problems in the exercises can be settled by today:)
 

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