Find C vector, with two known magnitudes

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Casodd
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Homework Statement


https://i.imgur.com/UtLzb34.png

Homework Equations


the law of cosinus

The Attempt at a Solution


I have not been available to scan my work, but I'm kinda stuck at the beginning. And our teacher have not show us this kind of physics yet.
Thanks.
 
Welcome to PF, what method have you already tried? I'm assuming you are using the tail-to-tip method since the law of cosines relevant. What exactly are you having trouble with?

Edit: I would appreciate even just a photo of your work (make sure its neat and legible).
 
So all I have to do is take the square root of ( |A|^2+ |B|^2cos79 ) ?
and then do tan delta to find the degree? (Which is not the question) ?
picture:
Hand-drawn vector diagram with x and y axes; vector A points up-left, vector B points left and slightly down, and -A points down-right, with C drawn from the origin. Angles of 42 degrees and 31 degrees are marked, and C = B-A with the law of cosines worked out below.


Thanks for answering.
 
Attachments
  • Hand-drawn vector diagram with x and y axes; vector A points up-left, vector B points left and slightly down, and -A points down-right, with C drawn from the origin. Angles of 42 degrees and 31 degrees are marked, and C = B-A with the law of cosines worked out below.
    Q87BV0L.png
    8.7 KB · Views: 889
Casodd said:
So all I have to do is take the square root of ( |A|^2+ |B|^2cos79 ) ?
and then do tan delta to find the degree? (Which is not the question) ?
picture:
View attachment 218369

Thanks for answering.
Yes, this looks accurate. That's how I did it. Good job!