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Homework Help: Thermal Energy Question

  • Thread starter yamm14
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  • #1
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Homework Statement:

A 150g steel spoon (constant = 420J/kg degrees Celsius) initially at 19 degrees Celsius is placed into a 250mL cup of water at 89 degrees Celsius. When both objects reach the same temperature what temperature will that be?

Relevant Equations:

change in energy = (mass)(constant)(change in temperature)
water constant = 4200J (kg degrees Celsius)
I don't know what to do!
 
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Answers and Replies

  • #2
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The spoon will cool down and lose energy, the water will warm up and gain energy. Use conservation of energy.
 
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  • #3
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