- #1
lxhull
- 4
- 1
- Homework Statement
- A thermos bottle contains 0.150 kg of water at 4.1 °C. When 9.00 x 10^-2 kg of a metal, initially at 96.2 °C, is put into the water, the temperature of the water rises to 21.7 °C. Calculate the specific heat of the metal
- Relevant Equations
- C= Eth/mT
Previously solved thermal energy gained by water as
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant
Eth= 0.15(4180)(17.6) = 11035.2 J
Not sure if its relevant