Homework help: Uncertainty with negative power

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Homework Help Overview

The discussion revolves around calculating the absolute uncertainty in the value of R^−2, given a measured distance R with an associated uncertainty. The subject area involves uncertainty analysis in measurements, particularly in physics or engineering contexts.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of relative and absolute uncertainties, with some questioning the correctness of the original poster's approach. There are mentions of significant figures and rounding issues that may affect the final result.

Discussion Status

The conversation includes various attempts to clarify the calculations and the impact of rounding on the final answer. Some participants suggest keeping extra digits during calculations or performing the entire calculation in one step to avoid intermediate rounding errors. There is no explicit consensus on a single correct method, but guidance has been offered regarding significant figures.

Contextual Notes

Participants note potential issues with significant figures and rounding in intermediate steps, which may influence the final uncertainty calculation. The original poster has acknowledged a correction in their rounding approach.

Jerry Z
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Question:
A distance R is measured to be 3.400 ± 0.007m. What is the absolute uncertainty in R^−2?

Attempted solution:
Relative uncertainty: 2* (0.007/3.4) = 4.11E-3;
R^-2 = 3.4^-2 = 0.0865 m^-2;
Absolute uncertainty = R^-2 * relative = 0.0865 * 4.11E-3 = 3E-4 m^-2;

Any help would be greatly appreciated!

EDIT: instead of 3E-4, the correct rounding should be 4E-4.
 
Last edited:
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Jerry Z said:
Question:
A distance R is measured to be 3.400 ± 0.007m. What is the absolute uncertainty in R^−2?

Attempted solution:
Relative uncertainty: 2* (0.007/3.4) = 4.11E-3;
R^-2 = 3.4^-2 = 0.0865 m^-2;
Absolute uncertainty = R^-2 * relative = 0.0865 * 4.11E-3 = 3E-4 m^-2;

Any help would be greatly appreciated!
Hello @Jerry Z . Welcome to PF !

What's your question?
 
SammyS said:
Hello @Jerry Z . Welcome to PF !

What's your question?
i cannot get the right answer for the question stated
 
Jerry Z said:
i cannot get the right answer for the question stated
Perhaps there is a problem with significant figures and/or rounding off at intermediate steps.
 
SammyS said:
Perhaps there is a problem with significant figures and/or rounding off in intermediate steps.
So I'm solving it correctly?
 
Jerry Z said:
So I'm solving it correctly?
What you did looks reasonable.

The details of getting uncertainties and applying rules for significant figures vary somewhat from book to book, instructor to instructor, discipline to discipline .

I suggest keeping two extra digits (over what's required for sig. figs.) .

OR

Do the entire calculation at one time with no intermediate steps. (Be especially careful of Order of Operations.)Do final rounding at the end to whatever decimal place is required in your situation.
 
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SammyS said:
What you did looks reasonable.

The details of getting uncertainties and applying rules for significant figures vary somewhat from book to book, instructor to instructor, discipline to discipline .

I suggest keeping two extra digits (over what's required for sig. figs.) .

OR

Do the entire calculation at one time with no intermediate steps. (Be especially careful of Order of Operations.)Do final rounding at the end to whatever decimal place is required in your situation.

Thank you so much! It is indeed the rounding in the end that made the difference.
 
Jerry Z said:
Thank you so much! It is indeed the rounding in the end that made the difference.
Great !

So, what was the acceptable answer?
 
SammyS said:
Great !

So, what was the acceptable answer?

Answer is edited in the original text. Thanks again!
 
  • #10
This is an example of the merits of keeping everything algebraic as long as possible, only plugging in values at the end. In the present case, when at last plugging in numbers, you would have had 2*0.007/3.43. Putting that into my calculator gives 0.000356.
 
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