What is the uncertainty in area and volume for a right circular cone?

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Homework Help Overview

The discussion revolves around calculating the uncertainty in the area and volume of a right circular cone, given specific measurements for the radius and height, along with their respective uncertainties.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of partial derivatives to derive expressions for uncertainty in area and volume. There are attempts to clarify the correct application of uncertainty formulas, with some participants questioning their calculations and the inclusion of different components of the area.

Discussion Status

Multiple participants have shared their calculated uncertainties for both area and volume, with some expressing uncertainty about their results. There is a suggestion to cross-check values for the area to resolve discrepancies, indicating an ongoing collaborative effort to clarify the calculations.

Contextual Notes

Participants note the importance of including both the base and lateral areas in their calculations, which has led to differences in results. There is also mention of using tools like spreadsheets to assist in computations.

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Uncertainty partial derivatives

Homework Statement



1 a) Give expressions for the uncertainty in both the area and volume of a right circular cone with radius R and height H and side length S. Assume that the radius has uncertainty σR and the height has an uncertainty σH. <----First part that I got.

b) For a radius R = 10.0 ± 0.1 cm and height H = 15.0 ± 0.2 cm, calculator the absolute uncertainty on both the area and the volume.

Homework Equations


Surface area A = ∏*R^2 + (PI)*S*R
Volume V = (1/3)*∏*R^2*H
(S = sqrt(R^2 + H^2))

The Attempt at a Solution



Ok so my attempt at solving this question was as follows


I tried to figure out the partial derivative with respect to the radius, and with respect to the height. When you get those the formula is



I was having trouble using the latex math equations thing so I just took a picture and here it is...
if it is unclear sigma and delta mean the same thing.

2lw6ull.png

qo920g.png


now I plugged in the values R = 10.0 ± 0.1 cm and height H = 15.0 ± 0.2 cm, and I got some absurdly high values, am I right, or did I do something wrong in my partial derivatives?
 
Last edited:
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Your equations are correct, except that their left-hand sides must have squares of the deltas.
 
So for the volume the uncertainty is + or - 37.8, and the uncertainty for area is + or - 13.7? Did I plug them in correctly now?
 
I get the same for the volume, but 14.6 for the area. I ended up using a spreadsheet to compute things after a few blunders :)
 
I'm seeing ~ 9.1 for the area (just saying...).
 
Oh my...which one is right. I don't knowww
 
Since we all seem to agree on the volume, consider it correct. For area, I suggest you post the value you get for each term in the equation, so that we could then cross-check.
 
I get 187.4 for the first section until sigma r, then 27.33 for the rest. Then I add them and take the square root and get 14.6.
 
I get the same results. Perhaps gneill could comment on his numbers.
 
  • #10
voko said:
I get the same results. Perhaps gneill could comment on his numbers.

Okay, I see that the base surface area is to be included and not just the lateral area of the right circular cone. I didn't notice that before :blushing: , so that explains a source of difference. My bad.

Designating the differentials of the Area as DAr and DAh, and dropping the units for the calculations so that r = 10.0, h = 15.0, then I find (keeping extra decimal places for intermediate calculations):

DAr = 136.894
DAh = 26.140

and so
$$δA = \sqrt{DA_r^2 δr^2 + DA_h^2 δh^2} = 14.6$$
 

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