# Homework problem - MasteringPhysics.com (electric potential)

• adam32386
In summary, electric potential is the measure of electric potential energy per unit charge in an electric field, measured in volts. To solve a homework problem related to electric potential on MasteringPhysics.com, one should carefully read and understand the problem, identify given information and what is being asked, use equations and principles, and double check the answer. The formula for electric potential is V = kQ/r, where k is Coulomb's constant, Q is the charge, and r is the distance. Distance affects electric potential inversely - as the distance increases, the electric potential decreases due to the decrease in electric field strength. Electric potential has many real-life applications, such as in designing circuits, understanding lightning, and developing technologies like batteries and capacitors
adam32386
In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053nm.

What is the electric potential of the proton at the position of the electron?

What is the electron's potential energy?

(do i use the area on a circle in this equation? or is this an answer with constants in the solution?) if you guys could help me figure this out I would appreciate it.
thank you.

Start with this: what's the equation for electric potential due to a point charge?

The electric potential of the proton at the position of the electron can be calculated using the equation V = kQ/r, where k is the Coulomb's constant, Q is the charge of the proton, and r is the distance between the proton and electron. Plugging in the given values, we get:

V = (9x10^9 N*m^2/C^2)(1.6x10^-19 C)/(0.053x10^-9 m) = 2.86x10^9 V

This means that at a distance of 0.053nm, the proton has an electric potential of 2.86x10^9 volts.

To calculate the electron's potential energy, we can use the equation U = -kQq/r, where U is the potential energy, k is the Coulomb's constant, Q and q are the charges of the proton and electron respectively, and r is the distance between them. Plugging in the given values, we get:

U = -(9x10^9 N*m^2/C^2)(1.6x10^-19 C)(-1.6x10^-19 C)/(0.053x10^-9 m) = -4.86x10^-18 J

Therefore, the electron's potential energy is -4.86x10^-18 joules at a distance of 0.053nm from the proton. Note that this is a negative value, indicating that the electron has a lower potential energy when it is closer to the proton.

## 1. What is electric potential?

Electric potential is the amount of electric potential energy per unit charge at a certain point in an electric field. It is measured in volts (V) and can be thought of as the electrical potential difference between two points.

## 2. How do I solve a homework problem on MasteringPhysics.com related to electric potential?

The first step is to carefully read and understand the problem. Then, identify the given information and what is being asked. Next, use equations and principles from your textbook or lecture notes to solve the problem. Finally, double check your answer and make sure it is reasonable.

## 3. What is the formula for electric potential?

The formula for electric potential is V = kQ/r, where V is the potential in volts, k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), Q is the charge in Coulombs, and r is the distance from the charge in meters.

## 4. How does distance affect electric potential?

The electric potential is inversely proportional to the distance from the source charge. This means that as the distance increases, the electric potential decreases. This is because the electric field strength decreases as the distance increases.

## 5. Can I use the concept of electric potential in real-life applications?

Yes, the concept of electric potential is used in many real-life applications, such as in designing electrical circuits, understanding the behavior of lightning, and developing technologies like batteries and capacitors. It is also important in understanding the flow of electricity in power grids and electronic devices.

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