Homomorphisms and isomorphisms

  • Thread starter Thread starter happyg1
  • Start date Start date
  • Tags Tags
    Homomorphisms
Click For Summary
SUMMARY

The discussion focuses on the properties of linear transformations defined by a mapping T from a vector space V, using bases v_1, v_2,..., v_n and elements w_1, w_2,..., w_n in V. It establishes that T is a homomorphism if it preserves the structure of V. For T to be an isomorphism, the elements w_i must form a basis of V, ensuring that the kernel of T is zero, which is a necessary condition for injectivity.

PREREQUISITES
  • Understanding of linear transformations and their properties
  • Knowledge of vector spaces and basis concepts
  • Familiarity with homomorphisms and isomorphisms in linear algebra
  • Ability to work with linear combinations and kernel of transformations
NEXT STEPS
  • Study the definition and properties of linear transformations in depth
  • Learn about the implications of the kernel and image of a linear transformation
  • Explore the relationship between bases and dimension in vector spaces
  • Investigate examples of homomorphisms and isomorphisms in various vector spaces
USEFUL FOR

Students and educators in linear algebra, mathematicians exploring vector space theory, and anyone interested in the foundational concepts of homomorphisms and isomorphisms.

happyg1
Messages
304
Reaction score
0

Homework Statement



Let[tex]v_1,v_2,...v_n[/tex] be a basis of V and let [tex]w_1,w_2,...w_n[/tex] be any n elements in V. Define T on V by
[tex](\lambda_1 v_1+\lambda_2 v_1+...+\lambda_n v_n)T=\lambda_1w_1+...\lambda_n w_n.[/tex]
a)Show that R is a homomorphism of V into itself.
b)When is T an isomorphism?

Homework Equations


An isomorphism is a 1-1 mapping.


The Attempt at a Solution


I think I have part a) done, although It makes more sense to me to prove that T is a Hom, not R...not sure where the R came from.

For part b, I am thinking that since the [tex]v_i[/tex] are a basis that the Iso would be true if the w's were a basis also?
IK know that an iso occurs when the Kernel is zero..but I'm still kinda confused here.
Any hints or advice will be appreciated.
Thanks,
CC
 
Physics news on Phys.org
Obviously, in order for T to be an iso, w_i must be a basis - the image lies in the span of the w_i, and that can only be all of V if they are a basis. That says T an iso implies w_i a basis. What about the converse?

Now, suppose that v is sent to zero by T, i.e. vT=0. Then what does that say about the linear combination of the w_i that v is sent to?
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K