How Do You Calculate Spring Extension in a Series Configuration?

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SUMMARY

The discussion focuses on calculating the extension of four springs connected in series, each supporting a mass m. The spring constant is denoted as k, and the gravitational force is represented by mg. The equilibrium equation for the second mass (m2) is established as 0 = ky2 - ky3 - mg, which allows for solving the extensions of the springs using known variables. Participants confirm the accuracy of the approach, emphasizing the importance of correctly identifying the forces acting on each mass.

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  • Understanding of Hooke's Law (f = ky)
  • Basic knowledge of Newton's second law of motion
  • Familiarity with concepts of equilibrium in mechanical systems
  • Ability to manipulate algebraic equations
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  • Study the derivation of spring extension formulas in series configurations
  • Learn about the implications of mass-spring systems in physics
  • Explore advanced applications of Hooke's Law in real-world scenarios
  • Investigate the effects of varying spring constants on system behavior
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Students studying physics, particularly those focusing on mechanics and spring dynamics, as well as educators seeking to enhance their teaching of equilibrium and force concepts.

bmxicle
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Homework Statement


4 springs with a mass on each end are connected in series as below:

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m1
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m2
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m3
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m4

All the masses are mass m, the length of each spring is 1, and the spring constant is k, find the extension of each spring.


Homework Equations



f = ky

The Attempt at a Solution



So basically if i label each spring extension as y_1, \ y_2, \ y_3, \ y_4 then the only forces are the spring pulling from above, the spring pulling from below and the force of gravity on each mass. So for example for the second mass m2 from the top the equilibrium equation would be:

0 = ky_2 - ky_3 -mg

If this is right I can solve the rest of the problem easily, but I'm just getting thrown off by my use of Newton's second law here.
 
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0=ky2−ky3−mg

This seems to be an accurate statement.

Now how can you rewrite the ky2 and ky3s into the variables you do know, which are m, k and g?
 
bmxicle said:
... the only forces are the spring pulling from above, the spring pulling from below and the force of gravity on each mass. So for example for the second mass m2 from the top the equilibrium equation would be:

0 = ky_2 - ky_3 -mg
Yes, you are on the right track.
 
Thanks, I can solve the rest of it pretty easily now. I think I was just over thinking which springs were pulling where.
 

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