Hooke's Law vs. Conservation of Energy

Click For Summary

Homework Help Overview

The discussion revolves around two physics problems related to Hooke's Law and the conservation of energy. The first problem involves a student standing on springs and determining the compression of each spring, while the second problem concerns a ball attached to a spring and how far it falls before being stopped by the spring.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of Hooke's Law and conservation of energy for the respective problems. There are questions about how to choose the appropriate method when unsure of the answers. Some participants discuss the implications of static versus dynamic situations and the differences in equilibrium positions versus distances fallen.

Discussion Status

Participants are actively engaging with the problems, questioning the methods and assumptions involved. There is mention of potential pitfalls in applying the wrong method, and some guidance is offered regarding the interpretation of the problems, although no consensus has been reached.

Contextual Notes

There is a noted concern about the interpretation of equilibrium positions and the effects of using conservation laws in static versus dynamic contexts. Participants are also considering the implications of misapplying methods, which could lead to incorrect answers.

keroberous
Messages
15
Reaction score
1
Homework Statement
I can never quite remember when solving problems with elastic materials whether I should be using Hooke's Law or conservation of energy. Below are two sample problems.
Relevant Equations
Hooke's Law: ##F=kx##
Elastic Potential Energy: ##E_e=\frac{1}{2}kx^2##
Gravitational Potential Energy: ##E_g=mgh##
Here are the two questions I want to compare:

1. A student of mass 62 kg stands on an upholstered chair containing springs, each of force constant 2.4 × 103 N/m. If the student is supported equally by six springs, what is the compression of each spring?

2. A 0.20-kg ball attached to a vertical spring of force constant 28 N/m is released from rest from the unstretched equilibrium position of the spring. Determine how far the ball falls, under negligible air resistance, before being brought to a momentary stop by the spring.

I can get the right answer for both questions, by using Hooke's law for number 1 and conservation of energy for question 2. My question is if I didn't know what the answers were, how would I choose the method? By using the incorrect method I'm off by a factor of two in both cases (bigger in 1 and smaller in 2).
 
Physics news on Phys.org
keroberous said:
Here are the two questions I want to compare:

1. A student of mass 62 kg stands on an upholstered chair containing springs, each of force constant 2.4 × 103 N/m. If the student is supported equally by six springs, what is the compression of each spring?

2. A 0.20-kg ball attached to a vertical spring of force constant 28 N/m is released from rest from the unstretched equilibrium position of the spring. Determine how far the ball falls, under negligible air resistance, before being brought to a momentary stop by the spring.

I can get the right answer for both questions, by using Hooke's law for number 1 and conservation of energy for question 2. My question is if I didn't know what the answers were, how would I choose the method? By using the incorrect method I'm off by a factor of two in both cases (bigger in 1 and smaller in 2).
In question 1, you are asked to determine the equilibrium position of the system (student plus springs). In question 2, you are asked how far the ball would fall before it reverses direction. This is not the same as the equilibrium position and would in fact be twice as far from the initial position as the equilibrium position.
Each method, used correctly, should give you the right answer to each question. If you were to post your solutions, we could comment on where you went wrong.
 
tnich said:
Each method, used correctly, should give you the right answer to each question.
But... in 1, it is a static arrangement. A conservation law is only directly useful when something has changed.
Conversely, in 2, it is not obvious how to find the force when the velocity is zero.
To apply energy in 1 or Hooke in 2 seems to require performing the conversion, i.e. integrating Hooke or differentiating energy.
 
Any reason you can't turn 1) into a dynamic situation and equate the PE lost by the man with the PE gained by the spring...

mgh=0.5kh^2

Solve for h.
 
CWatters said:
Any reason you can't turn 1) into a dynamic situation and equate the PE lost by the man with the PE gained by the spring...
Yes, there is a reason. That will give twice the correct answer, as @keroberous found and @tnich explained.
 
  • Like
Likes   Reactions: CWatters
Palm -> Face
 

Similar threads

Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
17
Views
2K
Replies
7
Views
4K
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
24
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K