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Horizontal Force on Pivot Point

  1. Nov 16, 2008 #1
    1. The problem statement, all variables and given/known data
    [​IMG]


    2. Relevant equations

    T=F*r
    F*X=Ia
    I=ML2/3

    3. The attempt at a solution
    I was able to do part A easily enough, but I'm not quite sure where to even start with part B. I know that the force on the pivot point would be F0 if X was .5L, ie the center of mass. However, I am unable to come up with the equation asked for. Thanks for any help!
     
  2. jcsd
  3. Nov 17, 2008 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Epif! :wink:

    Hint: take moments about any point on the rod (might as well use the c.o.m.), and use "impulsive" torque = change of angular momentum. :smile:
     
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