- #1

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- Homework Statement
- Ball of mass mb and velocity vb hits rod of length L , Rod pivots about the center. What is the angular momentum aafter impact?

- Relevant Equations
- I = 1/12 (mR^2)

I = mR^2

**Homework Statement::**Ball of mass mb and velocity vb hits rod of length L , Rod pivots about the center. What is the angular momentum aafter impact?

**Homework Equations::**I = 1/12 (mR^2)

I = mR^2

See the attached figure. I understand the concept of linear and angular momentum separately but I am confused as to how to use both at the same time. In the attached diagram ball B hits a rod that pivots in the center. In this case we have a classic case of conservation of angular momentum. However, if the rod is free to move, i.e. not connected at the center to the pivot, then the rod would move horizontally as well as rotating. I am having trouble finding an explanation as to how to add the linear momentum to the equation. Are they handled separately or can I have one equation for the angular part and another for the linear part?

I know that initially I would have a linear momentum of the ball being Mb X Vb. Would this be equal to the Mr X Vr where Vr is the linear velocity of the center of mass?