Hot Air Balloon Descent: Does it Keep Accelerating Until Impact?

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SUMMARY

The discussion centers on the descent behavior of hot air balloons, specifically whether they continue to accelerate until impact. It is established that if air resistance is present, the balloon will not accelerate indefinitely but may reach terminal velocity. The balloon's buoyancy changes as it descends due to increasing atmospheric density, which complicates the acceleration dynamics. The conversation references the Millikan experiment to illustrate the principles of buoyancy and resistance, concluding that in a hypothetical atmosphere with constant pressure, the balloon would accelerate downward until it crashes if air resistance were absent.

PREREQUISITES
  • Understanding of buoyancy principles in fluid dynamics
  • Familiarity with terminal velocity concepts
  • Knowledge of adiabatic processes and the adiabatic lapse rate
  • Basic principles of hot air balloon operation, including propane burner and vent controls
NEXT STEPS
  • Research the effects of atmospheric density on buoyancy in hot air balloons
  • Study the concept of terminal velocity in various mediums
  • Explore the principles of adiabatic processes in thermodynamics
  • Investigate the impact of air resistance on different shapes and sizes of objects in free fall
USEFUL FOR

Aerospace engineers, physics students, and hot air balloon operators seeking to understand the dynamics of balloon descent and the effects of buoyancy and air resistance.

frankcm
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If a hot air balloon cools enough to start descending, does it keep accelerating until it hits the ground? Assume that the air inside does not cool off anymore, and pretend that the air pressure stays the same at all altitudes. I tried testing it by dropping a coin into a pool. It didn't seem to accelerate but I think it might have reached terminal velocity from the water's "wind resistance".
 
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I don't know the answer for it likely depends on the initial height and whether there is a function to influence the air resistance, e.g. a valve. However, there won't be an increasing acceleration. E.g. the Millikan experiment is based upon this.

You might want to read about the terminal velocity: https://en.wikipedia.org/wiki/Terminal_velocity
 
All other things equal, the balloon will become more buoyant as it descends because atmospheric density goes up as altitude decreases. So it's possible the balloon will accelerate (in the form of slowing down).
 
David Lewis said:
All other things equal, the balloon will become more buoyant as it descends because atmospheric density goes up as altitude decreases. So it's possible the balloon will accelerate (in the form of slowing down).
The balloon is under ambient pressure regardless. Its density increases as well. A simple comparison of balloon initial density versus atmospheric density as a function of altitude will not yield a correct answer here.

As the balloon descends and is compressed under increased ambient pressure, it does not maintain its initial temperature. It is compressed in an adiabatic fashion and heats up. One might be tempted to think that this will cause it to gain increased buoyancy. But there is a complication. All things being equal, the atmosphere maintains a temperature differential of its own -- the adiabatic lapse rate.

But all of that is irrelevant. Look back at the initial post. We are asked to consider an atmosphere with constant pressure at all altitudes.

If there is air resistance, then fresh_42 nailed the answer. If there were no air resistance (an unrealistic atmosphere with no viscosity) then indeed, the balloon would accelerate downward until finally crashing into the ground

fresh_42 said:
whether there is a function to influence the air resistance, e.g. a valve.
The controls in a hot air balloon are on the propane burner (heating) and on a vent at the top of the balloon (cooling). Neither of these has a significant effect on the huge air resistance of an inflated balloon.
 
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fresh_42 said:
I don't know the answer for it likely depends on the initial height and whether there is a function to influence the air resistance, e.g. a valve. However, there won't be an increasing acceleration. E.g. the Millikan experiment is based upon this.

You might want to read about the terminal velocity: https://en.wikipedia.org/wiki/Terminal_velocity

I'm not so sure... Millikan's drops were stable in mass and volume, but a descending hot-air balloon will probably lose volume and gain mass. That must result in a continually decreasing buoyancy. Hence, the speed will increase...
 

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