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Homework Help: Household currents physics homework

  1. Jan 29, 2014 #1
    1. The problem statement, all variables and given/known data
    Typical household currents are on the order of a few amperes.
    If a 1.60A current flows through the leads of an electrical appliance, how many coulombs pass through it in 6.50min ?

    2. Relevant equations


    3. The attempt at a solution

    6.50min=1min/60s= 0.108s

    1.60A*0.108s= 0.173C

    I figured that delta Q would be in Coulombs but I was wrong. What further step do I need to do?
  2. jcsd
  3. Jan 29, 2014 #2


    Staff: Mentor

    amp = colombs/sec


    so your mistake is 6.5min = 0.108sec (ie 6 mins = one tenth of a second ??? Does that make sense?

    6.5 min= (6.5*60) secs = 390 secs

    colombs = 1.6 * 390 = ???
  4. Jan 29, 2014 #3
    Yes I just figured it out! thanks I notice my mistake after looking back at my calculations
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