MHB How about this? What is the inverse of a permutation cycle?

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    Cycle Permutation
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The discussion focuses on the inverse of a permutation cycle, specifically examining the cycle notation and its properties. It highlights that the inverse of a cycle, such as $(a_1 a_2 \dots a_n)^{-1}$, reverses the order of the elements. An example is provided with the cycles $(a b c d)$ and $(d c b a)$, demonstrating how elements are mapped back to their original positions. The conclusion drawn is that the product of a cycle and its inverse results in the identity permutation, represented as 1. Understanding these properties is essential in the study of permutation groups.
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$\tiny{412.5.9}$
this is under the section on Permutation Groups

What cycle is $(a_1a_2\dots a_n)^{-1}$

ok thot there would be and east theorem on this but can't find
 
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How about this? reverse the order

$(a b c d ) (d c b a ) $ a goes to b from the first then the second send b to a.

So

$(a_1 a_2 a_3 a_4 \cdots a_n) (a_n a_{n-1} \cdots a_2 a_1 ) = 1 $
 
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