How Accurate is the Calculated Inductance of 74mH in a Series RL Circuit?

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SUMMARY

The inductance of a series RL circuit with a resistance of 1.0 K ohms, where the current reaches 1/3 of its final value in 30 microseconds, is definitively calculated to be 74mH. The calculation utilizes the formula i(t) = I (1 - 1/e^(t/τ)), leading to the time constant τ being approximately 74 microseconds. Substituting the values confirms that the inductance L is indeed 74mH, validating the answer against the provided options.

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snipaj9696
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I would like to verify these answers please..

What is the inductance of a series RL circuit in which R=1.0 K ohms if the current increases to 1/3 of it's final value in 30 Ms (M is the greek symbol Mu).

Is the answer 30 (none of these) or is it 74mH?? I calculated 74mH

i(t) = I (1-1/e^t/τ)

given i(t) = 1/3*I and t =30uS and τ =L/R

so,,substitutin these values

we get t/τ = 0.41

30*10^-6 / τ = 0.41

τ ˜ 74 μ sec

L/R ˜ 74usec

R = 1K

so,,L ˜74mH




The choices for answers are.

1.) 49
2.) none of these
3.) 99
4.)74
5.) 62

thankyou!
 
Last edited:
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I get 74mH too.
 

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