- #1

Adeopapposaurus

- 3

- 0

- Homework Statement
- The speed of the boat on the water without stream is v_1 = 5 m/s. The water flows in the river parallel to the shore at a speed of v_2 = 3 m/s.

How should the boat be directed to cross the river in a direction perpendicular to the shores (What should be the angle between the boat and the shore)?

How long it takes for the boat across the river which is 80 meters wide?

- Relevant Equations
- arccos = (vr/vu)

a^2+b^2+c^2

v upstream = 5 - 3 =2

v of the water = 3

arccos = (2/3) = 48.19

v across the river = c^2 - a^2 = b^2

√3^2 - 2^2 = 6m/s

t = 80/6 = 13.3

can someone please point out my mistakes? am I even supposed to solve for angle like this or "perpendicular to the shores" just means that the angle is supposed to be 90 degrees?

v of the water = 3

arccos = (2/3) = 48.19

v across the river = c^2 - a^2 = b^2

√3^2 - 2^2 = 6m/s

t = 80/6 = 13.3

can someone please point out my mistakes? am I even supposed to solve for angle like this or "perpendicular to the shores" just means that the angle is supposed to be 90 degrees?