How to Calculate the Angle for a Boat Crossing a River with a Current?

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SUMMARY

The problem involves calculating the angle at which a boat must be pointed upstream to cross a river with a current. The boat travels at 4.0 km/h in still water while the current is 2.0 km/h. The correct angle to achieve a straight crossing is 30 degrees, determined using the sine function. Initial attempts using inverse tangent and cosine functions yielded incorrect angles of 63 and 60 degrees, respectively.

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  • Understanding of basic trigonometric functions (sine, cosine, tangent)
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  • Ability to draw and interpret diagrams related to motion
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Homework Statement



A boat that can travel at 4.0km/h in still water crosses a river with a current of 2.0 km/h. At what angle must the boat be pointed upstream (that is, relative to its actual path) to go straight across the river?

Homework Equations



No equations were given but it seems like a simple trig problem, just can't get the right answer

The Attempt at a Solution



My first attempt i used inverse tan theta (4/2) and got an angle of 63
My second attempt i used inverse cos theta (2/4) and got an angle of 60

the actual answer is 30. Either there is a very big step I'm missing or I've drawn something horribly wrong.
 
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bajangal1 said:

Homework Statement



A boat that can travel at 4.0km/h in still water crosses a river with a current of 2.0 km/h. At what angle must the boat be pointed upstream (that is, relative to its actual path) to go straight across the river?

Homework Equations



No equations were given but it seems like a simple trig problem, just can't get the right answer

The Attempt at a Solution



My first attempt i used inverse tan theta (4/2) and got an angle of 63
My second attempt i used inverse cos theta (2/4) and got an angle of 60

the actual answer is 30. Either there is a very big step I'm missing or I've drawn something horribly wrong.

The first thing to determine is which angle is meant. Is the angle measured from the bank of the river to the boat's velocity vector, or is it measured from a line perpendicular to the bank? After that it's a matter of drawing the diagram and labeling the appropriate sides with the given information.
 
Ok i think i was drawing it wrong. i drew it differently and used sin inverse (2/4) and got the right answer. thanks!
 

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