How can an object tip and slip at the same time?

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Conductivity
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The conditions are for tipping and slipping. Tipping: If P critical < Us N then it tips

Slipping: If P critical > Us N then it slips

What if we have P critical = Us N. Any increase will make it slide and tip...?

If we took a rectangular shape object with Height h and length L so half its length is b. We get that if we want the object to tip if p is acting at the highest point we get, P*h =w b. If we want P at this point to equal the static friction then, P = Us N, wb/h = Us W So Us must equal b/h
 
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Conductivity said:
How can an object tip and slip at the same time?
I take it you've never been ice skating :smile:
 
phinds said:
I take it you've never been ice skating :smile:
Or bowling.
 
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Or watching cars skid and roll.

Conductivity said:
The conditions are for tipping and slipping. Tipping: If P critical < Us N then it tips Slipping: If P critical > Us N then it slips

Cite your source please. And check to see that it says that when the object starts tipping that it stops slipping.
 
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Conductivity said:
How can an object tip and slip at the same time?
When sliding over a level surface? When the kinetic friction coefficient is greater than: horizontal_COM_to_base_edge_distance / vertical_COM_position.
 
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anorlunda said:
Or watching cars skid and roll.
Cite your source please. And check to see that it says that when the object starts tipping that it stops slipping.
It is just my college book, It didn't mention that.

I just wanted to know how the object will behave when it is about to tip and slip and you increase the force by a tiny amount. How the math will work out?