How Can Fixed Points Determine Solutions in Differential Equations?

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Homework Help Overview

The discussion revolves around the use of fixed points to determine solutions in differential equations, specifically through the application of a mapping defined by an integral involving cosine functions. Participants are exploring the continuity of the mapping and its implications for finding solutions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulation of the mapping \(\Theta\) and question whether a function \(f\) should be replaced with \(x\) in the context of the problem. There is also inquiry into the conditions under which \(\Theta\) is a contraction and the implications of continuity for the mapping.

Discussion Status

The conversation is ongoing, with participants seeking clarification on the continuity of the mapping \(\Theta\) and its role in the problem. Some guidance has been offered regarding the need to check continuity before proceeding with the solution, but no consensus has been reached on the specific steps to take.

Contextual Notes

Participants are operating under the constraints of homework rules, which may limit the depth of assistance provided. The original poster expresses uncertainty about the second part of the problem, indicating a need for further exploration of the concepts involved.

cummings12332
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Homework Statement



QQ截图20121202233027.png



The Attempt at a Solution



set x(t)=1+∫2cos(s(f^2(s)))ds(from 0 to t) then check x(0)=1+∫2cos(s(f^2(s)))ds(from 0 to 0)=1 then the initial condition hold, by FTC, we have dx(t)/dt=2cos(tx^(t)), then solutions can be found as fixed points of the map

but for secound part [0,T] i don't know how to begin can anyone help me ?
 
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cummings12332 said:

Homework Statement



View attachment 53573


The Attempt at a Solution



set x(t)=1+∫2cos(s(f^2(s)))ds(from 0 to t) then check x(0)=1+∫2cos(s(f^2(s)))ds(from 0 to 0)=1

Shouldn't that f be an x in this case?

but for secound part [0,T] i don't know how to begin can anyone help me ?

You have a map \Theta:\mathcal{C}([0,T],\mathbb{R})\rightarrow \mathcal{C}([0,T],\mathbb{R}) such that

\Theta(f):[0,T]\rightarrow \mathbb{R}:t\rightarrow 1+\int_0^t 2\cos(sf^2(s))ds

Strictly speaking, you first need to check that \Theta(f) is in fact continuous before you can say that the codomain of \Theta is \mathcal{C}([0,T],\mathbb{R}).

Now, you need to find out when \Theta is a contraction. Can you tell us what that means??

Also, here is a LaTeX guide on how to post mathematical equations: https://www.physicsforums.com/showpost.php?p=3977517&postcount=3 It would help us a lot if you would use this to make your equations more readable.
 
micromass said:
Shouldn't that f be an x in this case?
You have a map \Theta:\mathcal{C}([0,T],\mathbb{R})\rightarrow \mathcal{C}([0,T],\mathbb{R}) such that

\Theta(f):[0,T]\rightarrow \mathbb{R}:t\rightarrow\ 1+\int_0^t 2\cos(sf^2(s))ds<br /> <br /> Strictly speaking, you first need to check that \Theta(f) is in fact continuous before you can say that the codomain of \Theta is \mathcal{C}([0,T],\mathbb{R}).<br /> <br /> Now, you need to find out when \Theta is a contraction. Can you tell us what that means??<br /> <br /> Also, here is a LaTeX guide on how to post mathematical equations: <a href="https://www.physicsforums.com/showpost.php?p=3977517&amp;postcount=3" class="link link--internal">https://www.physicsforums.com/showpost.php?p=3977517&amp;postcount=3</a> It would help us a lot if you would use this to make your equations more readable.
<br /> <br /> how to say that \Theta(f) is continuous? i just don&#039;t know how to prove here. if it is then i know how to solve the problem now,many thanks
 
Last edited:
cummings12332 said:
how to say that \Theta(f) is continuous?

Fundamental theorem of calculus.
 

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