How can i calculate the exact amount of heat absorbed by a black paint?

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SUMMARY

The discussion focuses on calculating the exact temperature rise of black paint when exposed to a heat source, specifically through the lens of its heat absorption properties. Participants highlight the importance of the absorptivity coefficient (α), which quantifies the heat absorption capacity of a color. While the assumption is made that black paint absorbs up to 90% of heat, the lack of specific data on the heat absorption coefficient for black paint is noted as a significant gap. The conversation emphasizes the need for precise measurements and established coefficients to accurately determine temperature changes.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with absorptivity and emissivity concepts
  • Knowledge of color theory in relation to thermal properties
  • Basic thermodynamics
NEXT STEPS
  • Research the specific absorptivity values for various paint colors
  • Explore the concept of heat transfer coefficients in materials
  • Investigate methods for measuring temperature changes in painted surfaces
  • Learn about thermal radiation and its impact on color performance
USEFUL FOR

This discussion is beneficial for physicists, materials scientists, and anyone involved in thermal analysis or paint formulation, particularly those interested in the thermal properties of colors and their applications in design and engineering.

chetanladha
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Homework Statement


Hi.
Knowing the LRV, heat source and all other relevant details, how can we deduce the exact temp rise with black colour (or any other colour for that matter)??

The Attempt at a Solution


i think just like we do for metals, if we know the heat absorption coefficient, then it can be done.
But unfortunately i can't find anything named "heat absorption coefficient" for black colour.
Is there any equivalent?
 
Physics news on Phys.org
Well usually with a given paint color you can find out the absorptivity \alpha which will show how much heat it will absorb. I would assume that it will absorb up to 90% of the heat, but that may be wrong.
 

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