Fortran How can i create a random number distribution (FORTRAN)

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The discussion revolves around generating a random distribution of points within a unit sphere for the purpose of computing estimators related to the two-point correlation function in dark matter haloes. The user seeks to create an array with 3071 rows of random numbers within the interval (5, 29). Key methods for achieving this include generating three uniform random numbers in the range [-1, 1], normalizing them to ensure they lie on the sphere's surface, and using spherical coordinates with uniform angle generation. It's emphasized that to ensure a new distribution each time, the random number generator's seed should not be hard-set, but rather based on the current time. Additionally, achieving a uniform distribution of points over the sphere's surface is highlighted as a critical aspect, with caution against methods that may not yield uniformity. Suggestions include researching Fortran's intrinsic functions for random number generation and considering established libraries for assistance.
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Hello,

I am working on the two point correlation function in dark matter haloes.

Right now i need to create an array of rundom numbers to compute the estimators.

My question is:

How can i create a random distribution of points in the unit sphere (having in mind its curvature).

I want an array of random numbers 3071 rows, and the random numbers should be in the interval (5,29).

how can i do this?
(and every time i ran it a new distribution of points should arrise.)
 
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There are many ways to do this, and it will depend on details of your calculation which one is best (I don't understand what your numbers mean).

a) Generate three uniform numbers [-1,1], treat them as coordinates (x,y,z), if the point is inside the sphere consider this as a vector, normalize it and you get coordinates on the sphere.
b) Generate an angle uniformly between 0 and 2pi, generate the second angle with the right probability distribution
... google should find many more methods.
 
you mean you don't know how to do it? or you don't know how to do it in Fortran? either way this is something a google search should return lots of hits...typically random number generators return a number between 0 and 1 and it is up to you to turn it (proportionally) into the corresponding number within your desired range.

As far as 3071 rows...well, you need to do it 3071 times.

As far as different set every time...well, do not hard set the seed to the random number generator, retrieve the time, instead and use it.

As far as Fortran...google "fortran random" ...it should get hits where you will learn the names of the Fortran intrinsic functions for random number stuff.
 
gsal said:
typically random number generators return a number between 0 and 1 and it is up to you to turn it (proportionally) into the corresponding number within your desired range.

That is only half the issue. The other half is getting a uniform distribution of points over the area of the sphere (if that is what the OP meant by "a random distribution having regard to the curvature".

For eaxmple if you take x as a uniform random variable between -r and r, the y as a uniform random varuable between ##\pm\sqrt{r^2 - x^2}## and then calculate ##z = \pm\sqrt{r^2 - x^2 - y^2}## with a randomly chosen sign, you will NOT get a uniform distribution over the area. MFB's method looks right. The step "if the point is inside the sphere ... " is important!
 
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I used an imsllib (IMSL Library) a few years ago that had a subroutine called RNSPH
 
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