How can I deal with such an integral?

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    Calculus Integral
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SUMMARY

This discussion focuses on the challenges of integrating expressions where the integrand includes a variable with an unknown relationship to the variable of integration. Participants emphasize that if the variable, denoted as z, does not depend on x, it can be treated as a constant and factored out of the integral. However, if z has an unknown dependence on x, the integral cannot be computed until the relationship is established. Examples illustrate that different relationships yield different results, underscoring the necessity of knowing the function's form before integration.

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  • Familiarity with variable dependencies in mathematical expressions.
  • Knowledge of functions and their properties, particularly in relation to integration.
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Students, educators, and professionals in mathematics or engineering fields who are dealing with integrals involving variable dependencies and seeking to enhance their understanding of integration techniques.

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Homework Statement


How can I deal with such an integral: the integrand include another variable which has some relationship with the variable of integration, but i do not know the exact relationship. Can I just see the "another variable" mentioned above as a invariant and put it outside from the integral symbol?
I think I cannot do so, but how can I handle such a question?

Homework Equations


For example, dy=z*dx, where some unknown relationship with the x, i think i can't integral it m the two sides and just put the z outside from the integral symbol.

The Attempt at a Solution

 
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I think you are referring to the fundamental theorem of calculus?
 
MidgetDwarf said:
I think you are referring to the fundamental theorem of calculus?
I mean if i want to integral the dy=z*dx or something like this with an unknown z which may have some relation with the x, how can i do? Is there some area of mathematics concerning this kind of questions?
 
rtransformation said:
I mean if i want to integral the dy=z*dx or something like this with an unknown z which may have some relation with the x, how can i do? Is there some area of mathematics concerning this kind of questions?
If you're only dealing with the relationship between x and y as specified by dy and dx, then Z is just a constant i would image. Its like when you integrate and you get the + c constant added, but that C variable isn't one of the relationships in the equations.

so if you integrate z*dx then basically its just the integral of a constant with respect to x. And yeah you can just pull it out like a constant.
 
rtransformation said:

Homework Statement


How can I deal with such an integral: the integrand include another variable which has some relationship with the variable of integration, but i do not know the exact relationship. Can I just see the "another variable" mentioned above as a invariant and put it outside from the integral symbol?
I think I cannot do so, but how can I handle such a question?

Homework Equations


For example, dy=z*dx, where some unknown relationship with the x, i think i can't integral it m the two sides and just put the z outside from the integral symbol.

The Attempt at a Solution

This is pretty vague.

If z does not have a dependence on the variable of integration x, it can be treated as a constant.
If z does have some unknown dependence on the variable of integration, it cannot be treated as a constant, but you cannot integrate until the correct relationship between z and x is established.

For example, if z = ex, then ∫ z dx would give one result, but if z = sin (x), then ∫ z dx would give a completely different result.

That's just math. :frown:

BTW, you integrate functions, you don't 'integral' them.
 
SteamKing said:
This is pretty vague.

If z does not have a dependence on the variable of integration x, it can be treated as a constant.
If z does have some unknown dependence on the variable of integration, it cannot be treated as a constant, but you cannot integrate until the correct relationship between z and x is established.

For example, if z = ex, then ∫ z dx would give one result, but if z = sin (x), then ∫ z dx would give a completely different result.

That's just math. :frown:

BTW, you integrate functions, you don't 'integral' them.
haha, Thank you, i just can't remember the correct word, thank you again
isn't there exist a method to handle the uncertain z? that baffles me ...
 
rtransformation said:
haha, Thank you, i just can't remember the correct word, thank you again
isn't there exist a method to handle the uncertain z? that baffles me ...
Not that I'm aware of.
 
rtransformation said:
I mean if i want to integral the dy=z*dx or something like this with an unknown z which may have some relation with the x, how can i do? Is there some area of mathematics concerning this kind of questions?
I agree with SteamKing. In the integral ##\int z~ dx##, where z is some function of x, it's not possible to find an antiderivative without knowing how z is related to x.
 
Mark44 said:
I agree with SteamKing. In the integral ##\int z~ dx##, where z is some function of x, it's not possible to find an antiderivative without knowing how z is related to x.
Thank you
 

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