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How can i determine Specific heat capacity of Water cpv if i know all variables

  1. Dec 12, 2011 #1
    How can i determine Specific heat capacity of Water cpv if i know all variables

    If i use this equation:

    [(mi1 + mi2 +mv)cpv + mg*cpg]dT/dt = H

    mi1 = mass 1

    dT/dt = 0.05

    cpg = 890 J/(kg*K)

    mi2 = mass 2

    mv = mass 3

    H = 300 W

    masses are arbitrary numbers


    Its cpv that i should determine
     
  2. jcsd
  3. Dec 13, 2011 #2
    I'm assuming you're having difficulties solving the equation for [itex]cpv[/itex], in that case you need to give it a go and show us what you've done and where you're getting stuck. Your final answer should look like this, see if you can get it.
    [tex] cpv = \frac{\frac{H}{\frac{dT}{dt}} - mg cpg}{m_{i1} + m_{i2} + m_v} [/tex]
     
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