# How can i determine Specific heat capacity of Water cpv if i know all variables

1. Dec 12, 2011

### Firben

How can i determine Specific heat capacity of Water cpv if i know all variables

If i use this equation:

[(mi1 + mi2 +mv)cpv + mg*cpg]dT/dt = H

mi1 = mass 1

dT/dt = 0.05

cpg = 890 J/(kg*K)

mi2 = mass 2

mv = mass 3

H = 300 W

masses are arbitrary numbers

Its cpv that i should determine

2. Dec 13, 2011

### JHamm

I'm assuming you're having difficulties solving the equation for $cpv$, in that case you need to give it a go and show us what you've done and where you're getting stuck. Your final answer should look like this, see if you can get it.
$$cpv = \frac{\frac{H}{\frac{dT}{dt}} - mg cpg}{m_{i1} + m_{i2} + m_v}$$