How Can I Determine the Volume of a Diatomic Ideal Gas in a Rigid Container?

  • Thread starter Thread starter Latios1314
  • Start date Start date
  • Tags Tags
    Gas Moles
Click For Summary

Homework Help Overview

The discussion revolves around determining the volume of a diatomic ideal gas contained in a rigid container, initially at 300K and 1.3x10^5 Pa, which is heated to 330K. Participants explore various aspects of the problem, including the implications of heating, internal energy changes, and the nature of the gas's behavior under different conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between pressure, volume, and temperature for ideal gases, questioning how to find the volume without knowing the number of moles. Some participants reference the internal energy change and its dependence on temperature, while others inquire about the meaning of the last part of the question regarding a different compression process.

Discussion Status

Some participants have provided calculations for pressure and internal energy changes, while others are seeking clarification on specific concepts and equations related to ideal gases. There is an ongoing exploration of the implications of the rigid container and the nature of the gas's specific heat.

Contextual Notes

Participants note the absence of specific heat values in the problem statement and discuss assumptions about the specific heat of diatomic gases. There is also mention of the need for additional information regarding the number of moles to fully resolve the problem.

Latios1314
Messages
45
Reaction score
0
A diatomic ideal gas is in a rigid container at an initial sate of 300K and 1.3x10^5 Pa is heated to a final state of 330K by 623.25J of heat. calculate the pressure in the container after the heating, the work done by the gas, the change in internal energy and the volume of the container. if the same gas is now continued in another cylinder and is compressed with a different compression process from the same initial to final states as above, calculate the change of the internal energy. The universal gas constant is given as 8.31.

I 've managed to do the first three parts of the question but I'm curently stuck at finding the volume.

I've tried using pV=nRT but it doesn't work since i do not know the number of moles of gas present.

Aside from finding the volume, i don't really understand what does the last part of the question mean. Could someone explain it to me?
 
Physics news on Phys.org


For an ideal gas, internal energy is solely a function of temperature. It is computed by the following:

dU = Cv * dT where Cv is the constant volume specific heat and dT is temperature change.

If you don't know the quantity of gas, then the change in internal energy will be on a per unit mass. Note that above equation does not have mass term so it is per unit mass.

Do you know what polytropic processes are where P*V**n = constant, where n takes on different values based on whether process is isothermal, isometric, isentropic, or isobaric?
 


LawrenceC said:
For an ideal gas, internal energy is solely a function of temperature. It is computed by the following:

dU = Cv * dT where Cv is the constant volume specific heat and dT is temperature change.

If you don't know the quantity of gas, then the change in internal energy will be on a per unit mass. Note that above equation does not have mass term so it is per unit mass.

Do you know what polytropic processes are where P*V**n = constant, where n takes on different values based on whether process is isothermal, isometric, isentropic, or isobaric?

But specific heat isn't given in the question?

i do know what isothermal, isometric and isobaric means but i do not know about the P*V**n = constant equation.
 


Please show how you did the first three parts of the problem.
 


P1/T1=P2/T2
1.3 X 10^5 /300 = P2/330
P2=1.43 X 10^5 Pa

No work is done by gas since the volume of the container do not change.

Change in internal energy = heat, W=0
Hence, Change in internal energy = 623.25J
 


Latios1314 said:
P1/T1=P2/T2
1.3 X 10^5 /300 = P2/330
P2=1.43 X 10^5 Pa

No work is done by gas since the volume of the container do not change.

Change in internal energy = heat, W=0
Hence, Change in internal energy = 623.25J
Try to work out the number of moles from the heat capacity of this gas. The heat capacity is 623.25/30 = 20.775 Joules/K = 2.5R = 5R/2

The author of the problem should tell you what the Cv of this gas is since it is not possible to determine the Cv of a non-specfied diatomic ideal gas purely from theory. However, I think the author wants you to assume that the specific heat at constant volume is 5R/2. If so, how many moles are we dealing with?

[Note: The diatomic gas has three degrees of translational freedom. There are also possible degrees of rotational freedom (2) and vibrational freedom (2). Generally, the vibrational mode of most diatomic molecules is not active at temperatures of 300K so the vibrational modes do not contribute to the specific heat. However, at 300K, most gases will have 2 rotational degrees of freedom. So most diatomic gases in this temperature range will have a Cv = 5R/2 and a Cp = 7R/2].

AM
 

Similar threads

Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
10
Views
2K
Replies
5
Views
3K
Replies
49
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 49 ·
2
Replies
49
Views
9K
Replies
14
Views
2K
Replies
4
Views
3K
Replies
2
Views
2K