How can I explicitly compute the inverse of a vector valued function?

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SUMMARY

The discussion focuses on computing the explicit inverse of the vector-valued function defined as f = (f_1, f_2, f_3) with f_k(x_1, x_2, x_3) = x_k / (1 + x_1 + x_2 + x_3) for k = 1, 2, 3. The determinant of the Jacobian matrix is established as (1 + x_1 + x_2 + x_3)^(-4), confirming that the function is one-to-one due to the nonzero determinant. Participants conclude that while finding the inverse explicitly can be challenging, in this case, it can be achieved through algebraic manipulation of simultaneous equations.

PREREQUISITES
  • Understanding of vector-valued functions
  • Knowledge of the inverse function theorem
  • Familiarity with Jacobian matrices
  • Basic algebra for solving simultaneous equations
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  • Study the properties of Jacobian matrices in multivariable calculus
  • Learn about the inverse function theorem in detail
  • Practice solving simultaneous equations in multiple variables
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Students and educators in mathematics, particularly those studying multivariable calculus and vector analysis, as well as anyone interested in understanding the inverse of vector-valued functions.

Carl140
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Homework Statement



Let f= (f_1, f_2, f_3) be a vector valued function defined (for every
point (x_1,x_2,x_3) in R^3 for which x_1 + x_2 + x_3 is not equal to -1) as follows:


f_k (x_1,x_2,x_3) = x_k /( 1+x_1+x_2+x_3) where k =1,2,3.


After some computations I found that the determinant of the Jacobian
matrix is (1+x_1+x_2+x_3)^(-4) (which coincides with the answer of the book).
Then, by the inverse function theorem, it follows that f is one to one
since the determinant is nonzero.

The problem is the following:


Compute f^(-1) explicitly.


How can I do this?


http://en.wikipedia.org/wiki/Inverse_function_theorem


Gives a formula to find the inverse of the jacobian matrix, but I'm trying to find the inverse of the function.

How to do this?


The Attempt at a Solution



I don't see how to find the inverse explicitly, I know it exists because the determinant
of the Jacobian is nonzero everywhere.
 
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Nevermind, its just a system of equations =)
 
In general it can be hard or impossible to find a formula for the inverse. In this case it's easy because it's a simple function. Just use algebra. If f(x,y,z)=(a,b,c) can you find a formula for x, y and z in terms of a, b and c? That's three simultaneous equations in the three variables if you equate the components. Hint: add them.
 

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