MHB How Can I Maximize the Area of a Window Using These Equations?

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To maximize the area of a window using the given equations, first solve the perimeter equation for height (h) in terms of radius (r) and substitute this into the area equation. Next, differentiate the modified area equation with respect to r and set the derivative equal to zero to find the optimal radius. Finally, calculate the width of the window as 2r in meters for the maximum area. This approach effectively combines calculus with geometric principles to determine the best dimensions for the window.
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Does anyone know how to work this out. Any help much appreciated. it is question 32 I'm stuck on
 

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Two equations are relevant here:

$$A=\dfrac12\pi r^2+2rh\quad(1)$$

and

$$P=2h+2r+\pi r=2h+(2+\pi)r=12+3\pi\quad(2)$$

Now proceed as follows:

a) solve $(2)$ for $h$ in terms of $r$ and substitute that for $h$ in $(1)$, giving $(1*)$.

b) differentiate $(1*)$ with respect to $r$, equate the result to $0$ and solve for $r$.

c) state $2r$ in meters as the width of the window with maximum area.
 

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