How can I simplify adding two sine waves using trigonometric identities?

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To simplify the addition of two sine waves, y = Asin(wt) + Bsin(wt + x), one can use the trigonometric identity sin(u + v) = sin(u)cos(v) + cos(u)sin(v) to express sin(wt + x) in terms of sin(wt) and cos(wt). This allows the equation to be rewritten as Csin(wt) + Dcos(wt), where C and D are determined by the coefficients A and B. By applying the identity Csin(z) + Dcos(z) = Rsin(z + q), one can derive R and q, where R = sqrt(C^2 + D^2) and q = arctan(D/C). Ultimately, this results in the simplified form y = Rsin(wt + q), enabling further analysis or manipulation of the sine waves. This method provides a clear approach to combine sine functions using trigonometric identities.
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Add the following sine waves

y= Asin(wt) + Bsin(wt + x) Where w=2(pi)f and x is a phase shift


I SIMPLIFIED this for my friend using rotating vectors, then i got really annoyed realizing that I didn't know how to do it the direct way (trig identities).

So I've posted it here for all you smart folks to try
 
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What do you mean by solved?
 
Ok, after consideration, is this what you want?

We may use sin(u+v)=sinucosv+cosusinv to rewrite sin(wt+x) in terms of cos(wt) and sin(wt), and then collecting terms we can rewrite the equation as Csinwt+Dcoswt for some choice of C and D. You may then blindly apply a formula whose derivation comes from :

suppose Csinz+Dcosz= Rsin(z+q), then C = Rcos(q) and D=Rsin(q) after applying that identity, from which we see R=sqrt(C^2+d^2) and tan(q) = D/C ie q=arctan(D/C)

So, you may conclude that y= Rsin(wt+q) for suitable R and q which can be derived with a little work. You can use that to do most anything you wish now.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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