How can I solve for U2 in this equation?

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Homework Help Overview

The discussion revolves around solving for U2 in a mathematical equation involving algebraic expressions and operations. Participants are analyzing the equation's structure and the implications of parentheses in the calculations.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to manipulate the equation to isolate U2, while questioning the placement of parentheses and the validity of certain steps. There are discussions about the origins of specific numerical values and the correctness of algebraic manipulations.

Discussion Status

The conversation is ongoing, with participants providing feedback on each other's reasoning and calculations. There is a focus on clarifying the importance of parentheses and ensuring that expressions are handled correctly. Some guidance has been offered regarding the structure of the equations, but no consensus on the correctness of the final answer has been reached.

Contextual Notes

Participants are grappling with the implications of missing parentheses and the resulting confusion in the calculations. There is a noted emphasis on following strict rules in algebraic manipulation.

manal950
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I will try



391.4368 + 24.264U2 + 2.2332 / 0.8 = 30.5764/1
24.461 = 391.436+24.2564U2 + 12.232

24.461 - 391.436 - 12.232 = 24.2564U2
U2 = (24.461 - 391.436 - 12.232 ) / 24.2564
U2 = 15.6
 
Last edited by a moderator:
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Don't ignore parentheses.

You already made a mistake in your first step. Where did you got 2.2332 from?
 
391.4368 + 24.264U2 / 0.8 + (15.290U2) = 30.5764

Now what will I do

and this next ..

391.4368 + 24.264U2 + 2.2332 / 0.8 = 30.5764/1
 
Don't ignore parentheses. 391.4368 + 24.264U2 / 0.8 and (391.4368 + 24.264U2) / 0.8 are two different things.

Apart from lack of parentheses your first step looks OK now. But I still don't know where did you got 2.2332 from.

[tex]\frac{a+b}c = \frac a c + \frac b c[/tex]
 
391.4368 + 24.264U2 / 0.8 + (15.290U2) = 30.5764

391.4368 + 24.264U2 + (15.290U2) /0.8= 30.5764

now Is this step is correct ?
 
Last edited:
No, it is wrong. You can't move expressions at random, there are strict rules that you need to follow.

You are still ignoring parentheses, you are wasting your time and my time.
 
Borek said:
Don't ignore parentheses.

You already made a mistake in your first step. Where did you got 2.2332 from?
I think the 2.2332 is supposed to be 12.232, which is what you get by multiplying 15.290 by 0.8.
 
So now is my answer is correct or not ... ??
 
It's kind of hard to follow what you did, so I'd have to say "probably not." First, take the sage Borek's advice and use parentheses. As he noted, a+b/c means something completely different from (a+b)/c. Don't make others guess what you mean when you can write it in a way that's perfectly clear.

So you're starting off with

30.581((12.8+0.8u2)/0.8) + 15.290u2 = 30.5764.

Now show us one step at a time what you're doing. It might help if you explained in words that you're doing each step as well.
 
  • #10
30.581((12.8+0.8u2)/0.8) + 15.290u2 = 30.5764.

Now I will multiply 30.581 X ((12.8+0.8u2) / 0.8

= 91.4368 + 24.4648U2 /0.8 + 15.290u2 = 30.5764.

now I will bring 91.4368 other side
24.4648U2 /0.8 + 15.290u2 = 30.5764 - 91.4368
24.4648U2 /0.8 + 15.290u2 = -60.8604
now I will apply this rule a+b/c to left side
24.4648U2 + 15.290u2 /0.8 = -60.8604
Now
-60.8604 (0.8) = 24.4648U2 + 15.290u2
u2 = -9.6

Note : U2 the 2 is not square
 
  • #11
manal950 said:
30.581((12.8+0.8u2)/0.8) + 15.290u2 = 30.5764.

Now I will multiply 30.581 X ((12.8+0.8u2) / 0.8

= 91.4368 + 24.4648U2 /0.8 + 15.290u2 = 30.5764.
How did you get
$$91.4368 + \frac{24.4648u_2}{0.8} + 15.290u_2 = 30.5764?$$
 
  • #12
I think I know what is going on. You don't ignore parentheses - you have no idea they are necessary. You are consistently making the same error, which suggests you think (1+2)/3=1+2/3. That's incorrect. (1+2)/3=1/3+2/3. Each expression from the sum in the numerator must be divided separately.
 

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