How Can I Solve Question Type: "With Magnitude and Unit Vectors"?

AI Thread Summary
The discussion focuses on understanding the concept of vectors in physics, specifically regarding magnitude and unit vectors in the context of electric forces. A beginner seeks clarification on how to apply these concepts to solve problems involving charged spheres and Coulomb's Law. Participants emphasize the importance of recognizing that vectors have both magnitude and direction, and suggest starting with a coordinate system to visualize the problem. The expression for Coulomb's Law is provided, highlighting that it must be adjusted to reflect the vector nature of force. The conversation concludes with a reminder that the direction of the force depends on the nature of the charges involved.
denfaro
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Hi I am a beginner in this topic. I didn't understand this question type clearly.What does it mean" With Magnitude and Unit Vectors" exactly? May you help me for the solution step by step :). Thanks in advance.
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denfaro said:
Hi I am a beginner in this topic. I didn't understand this question type clearly.What does it mean" With Magnitude and Unit Vectors" exactly? May you help me for the solution step by step :). Thanks in advance.
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Welcome to the PF. :smile:

Your thread has been moved to the Schoolwork forums.

We cannot do your schoolwork/homework for you, but perhaps we can give you a few tips to help your understanding so that you can start working on the problem.

What have you done with vectors so far? You know that vectors have a magnitude and direction, right? And have you learned about coordinate systems like Caretesian coordinates, where there are x and y directions, etc.?
 
berkeman said:
Welcome to the PF. :smile:

Your thread has been moved to the Schoolwork forums.

We cannot do your schoolwork/homework for you, but perhaps we can give you a few tips to help your understanding so that you can start working on the problem.

What have you done with vectors so far? You know that vectors have a magnitude and direction, right? And have you learned about coordinate systems like Caretesian coordinates, where there are x and y directions, etc.?
Yes I learned the vectors,coordinate system but I don't know how can I use them on this question.
 
denfaro said:
Yes I learned the vectors,coordinate system but I don't know how can I use them on this question.
So start by drawing an x-y set of axes on the diagram. I would probably make the (0,0) point at the A charge, with the x-axis to the right and the y-axis pointing up.

Then write the general vector force equation for the force on one charge due the electric field from another charge (based on the amount of the charges and the separation distance).

Please do those things, and show us what you get. Thank you.
 
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denfaro said:
Yes I learned the vectors,coordinate system but I don't know how can I use them on this question.
Do you know charged spheres will apply force on each other?
 
Adesh said:
Do you know charged spheres will apply force on each other?
Yes I know
 
denfaro said:
Yes I know
What’s the expression for that force? I mean is there any law which governs how two charged spheres will apply force on each other ?
 
Adesh said:
What’s the expression for that force? I mean is there any law which governs how two charged spheres will apply force on each other ?
I think you mean Coulmb's Law
 
denfaro said:
I think you mean Coulmb's Law
Yes. Can you please write out the Coulombs Law?
 
  • #10
Adesh said:
Yes. Can you please write out the Coulombs Law?
F=(k*(q1*q2))/r^2.
 
  • #11
denfaro said:
F=(k*(q1*q2))/r^2.
But force is a vector quantity, the expression which you have given doesn’t involve the direction of the force. Can you fix it? Can you do something so that we get a vector quantity in that expression of Coulombs Law?
 
  • #12
Adesh said:
But force is a vector quantity, the expression which you have given doesn’t involve the direction of the force. Can you fix it? Can you do something so that we get a vector quantity in that expression of Coulombs Law?
Sorry I don't. How can I do that?
 
  • #13
denfaro said:
Sorry I don't. How can I do that?
$$\vec{F} = k \frac{q_1 ~q_2 }{r^2}~ \hat{r}$$ the force acts on the line joining the two charges.
 
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  • #14
Adesh said:
$$\vec{F} = k \frac{q_1 ~q_2 }{r^2}~ \hat{r}$$ the force acts on the line joining the two charges.
Thanks I have an idea now. :)
 
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  • #15
And it's important to remember that the force between like charges is repulsive, and the force between opposite charges is attractive. That's where the direction for the force vector comes from. :smile:
 
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