John999
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I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
The discussion focuses on solving the differential equation \(x \frac{dy}{dx} - 2y = x^2 \cos(x)\) with the initial condition \(y(\frac{\pi}{2}) = 0\). A suggested approach involves dividing the equation by \(x\) to facilitate the use of an integrating factor. This method allows for the transformation of the equation into a more manageable form, ultimately leading to a solution.
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Can one think of a way that xy'-2y looks like the derivative of a quotient?John999 said:I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks
John999 said:I'm having problems solving this differential equation:
x*dy/dx-2*y=(x^2)*cos(x)
y(pi/2)=0
Thanks