How Can I Solve This Division Problem?

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Homework Help Overview

The discussion revolves around a division problem, specifically focusing on the method of long division. The original poster expresses confusion regarding the process and seeks clarification on how to approach the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the mechanics of long division, with one providing a detailed example of dividing 63 by 5. Questions about the application of long division to a polynomial division problem are also raised.

Discussion Status

Some guidance has been offered through a detailed explanation of long division, including both numerical and polynomial examples. Participants are engaging with the content, and there is an acknowledgment of the challenges associated with understanding long division.

Contextual Notes

There is a mention of the original poster's attachment, which may contain additional context or specifics about the division problem in question. The discussion reflects a mix of humor and genuine inquiry, indicating varying levels of comfort with the topic.

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Homework Statement



I added an attachment... I am not understanding how they did this...
 

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Do you remember how to do long division with numbers?
For example, 6 / 5?
 
no that's hard.
 
Let me give you a couple of hints...
Suppose we want to divide 63 by 5:
Code:
5) 63 (
So we check how often 5 fits in 6. Clearly, that is once, so we write 1 x 5 below the 6 and subtract it, putting the 1 on the right:
Code:
5)63 (1
   5
   ---
   1
Now we pull down the 3, and repeat the trick:
Code:
5)63 (1
   5.
   -.
   13
5 fits in 13 two times, so we get:
Code:
5)63 (12
   5
   ---
   13
   10
   ---
     3
Indeed, 63 / 5 equals 12 (because 5 x 12 = 60) and then something. But suppose we want to find some more digits, for example the first decimal. We cannot take another 5 out of 3, so we add a zero:
Code:
5) 63. (12
   5 .
   --.
   13.
   10.
   --.
    30

Now we can take out 5, and we can take it out six times:
Code:
5) 63. (12.6
   5 .
   --.
   13.
   10.
   --.
    30
    30
    ---
     0
and we have nothing left, so 12.6 is the answer.

In your example, it is the same. If you want to take 1 + 3x² out of 2x, you can do so 2x times, and since 2x(1 + 3x²) = 2x + 6x³,
Code:
1 + 3x²) 2x         ( 2x
         2x + 6x³
        ---------
            - 6x³

Next, you can take it out 6x³ times, write that underneath, and subtract.
In principle you can keep on doing this as long as you want, but in your example they stop at some point, they just take what is left and write it at the end (in the numeric example, you could stop after
Code:
5)63 (12
   5
   ---
   13
   10
   ---
     3
and just say "I don't feel like keeping on doing this, so I'll just take the remainder and divide it by 5, which gives 12 + 3/5".
 
I was kidding, thank you though.
 
In that case, thanks for having me type it all out :P
You'd be surprised how many people are completely confused as soon as the words "long division" are said.
 
I'm sorry, i didnt thinnk you would type it all thge way out lol. But I do still appreciate your help.
 

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