How can I use this hint to help prove the limit using the definition?

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Homework Help Overview

The problem involves proving the limit \(\lim_{x\to 1^{+}}{\frac{x-3}{x-1}}=-\infty\) using the definition of a limit. The original poster is attempting to establish an inequality to demonstrate this limit, but is encountering difficulties in deriving the necessary conditions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster has set up the inequality \(\frac{x-3}{x-1} < - M\) but is unsure about the implications of this setup and how it leads to the desired result. Some participants question the clarity of the original poster's approach and the specific steps taken in their reasoning.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the original poster's attempts. A hint has been provided regarding the manipulation of terms, suggesting a potential avenue for further exploration, but no consensus or resolution has been reached.

Contextual Notes

The original poster has not fully detailed their reasoning process, which may be contributing to the challenges in understanding their approach. There is an emphasis on adhering to the limit definition in the context of the problem.

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Homework Statement


Hello, I have to prove, using the limit definition, that \lim_{x\to 1^{+}}{\frac{x-3}{x-1}}=-\infty


The Attempt at a Solution


I've set this unequation \frac{x-3}{x-1} &lt; - M but it doesn't lead to the result 1&lt;x&lt;1+\frac{2}{M+1}, what did I wrong ?

Thanks
 
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You do understand that we can't tell you what you did wrong if you don't tell us what you did, don't you?
 
I've set up this unequation \frac{x-3}{x-1} &lt; - M to prove the limit using its definition but it doesn't lead to the result 1&lt;x&lt;1+\frac{2}{M+1}
 
scientifico said:
I've set up this unequation \frac{x-3}{x-1} &lt; - M to prove the limit using its definition but it doesn't lead to the result 1&lt;x&lt;1+\frac{2}{M+1}

Hint: ##M+3 = (M+1) + 2##.
 

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