How Can Newton's Method Be Modified for Polynomial Congruences?

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SUMMARY

The discussion focuses on modifying Newton's Method for solving polynomial congruences of the form f(x) = 0 mod(p). The proposed modification involves using linear interpolation to derive the next approximation, expressed as x_{n+1} = x_{n} + (f(x_{n}) / f'(x_{n})) mod(p/f'(x_{n})). This approach aims to iteratively refine solutions to polynomial equations under modular arithmetic, specifically addressing the effectiveness of linear interpolation in this context.

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  • Understanding of polynomial functions and their derivatives
  • Familiarity with modular arithmetic and congruences
  • Knowledge of Newton's Method for root-finding
  • Basic concepts of linear interpolation in numerical methods
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  • Research the application of Newton's Method in modular arithmetic
  • Study polynomial congruences and their properties
  • Explore linear interpolation techniques in numerical analysis
  • Investigate iterative methods for solving equations in modular systems
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Mathematicians, computer scientists, and anyone interested in numerical methods for solving polynomial equations in modular arithmetic.

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Let be the congruence equation with f(x) a Polynomial of grade k then:

[tex]f(x)=0mod(p)[/tex]

then if we have as a first approximation [tex]f(x_{n+1})=0mod(p)[/tex]

then using a linear interpolation: [tex]f(x_{n})+f'(x_{n})(x_{n+1}-x_{n})=0mod(p)[/tex] or [tex]x_{n+1}=(x_{n}+\frac{f(x_{n}}{f'(x_{n})})0mod(p/f'(x_{n})[/tex]

So we have 'modified' Newton method for solving Polynomial congruences. :Bigrin:
 
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I think in this case the mai question is if the linear interpolation solution

[tex]f(x_{n})+f'(x_{n})(x_{n+1}-x_{n})=0mod(p)[/tex] (1)

will work to solve the general congruence [tex]f(x)=0mod(p)[/tex] for f(x) a POlynomial solving it by iterations using Newton method, where from (1) form an initial ansatz x_n we can get the next approximate value x_{n+1}
 

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