How Can Photons Have Momentum If They Have No Mass?

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Discussion Overview

The discussion revolves around the concept of photon momentum and the apparent contradiction of photons having momentum despite having no rest mass. Participants explore this topic through various theoretical frameworks, including classical and relativistic physics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question how photons can possess momentum if momentum is traditionally defined as p=mv, given that photons have no rest mass.
  • One participant introduces the Poynting vector as a classical explanation for the momentum of light, suggesting that this perspective may belong in a classical physics context.
  • Another participant discusses the relativistic definition of momentum, noting that as rest mass approaches zero and velocity approaches the speed of light, the expression becomes indeterminate, allowing for non-zero momentum under certain limit conditions.
  • It is mentioned that even with zero rest mass, the energy of a photon is related to its momentum through the equation E=cp, indicating that photons can still have momentum when energy is present.
  • A participant clarifies the distinction between proper mass and relativistic mass, asserting that the proper mass of a photon is zero, while its momentum can still be defined in terms of energy and speed.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of photon momentum, with some focusing on classical definitions and others on relativistic frameworks. There is no consensus on a singular explanation, and the discussion remains unresolved.

Contextual Notes

Limitations include the dependence on definitions of mass and momentum, as well as the unresolved nature of the mathematical expressions involved in the transition from classical to relativistic descriptions.

3dsmax
Wikipedia says that photons have momentum. How can that be possible since p=mv?
 
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3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?


The Poynting vector,S, gives momentum of light, and is given by:

S = E X B...E= electric field
B= magnetic field
X is cross product

However, this is the classical answer...and maybe this answer should be in classical section.:smile:
 
Last edited:
3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?

According to relativity, the spatial momentum of a "particle" that has rest mass [itex]m[/itex] is

[tex]p = \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}}.[/tex]

To consider a photon, let [itex]m \rightarrow 0[/itex] and [itex]v \rightarrow c.[/itex] This gives zero over zero, which is indeterminant, and can be anything (including non-zero values), depending on how the limits are taken.

Also, relaltivity says that for any particle,

[tex]E^2 - (cp)^2 = \left(mc^2\right)^2.[/tex]

Even if [itex]m=0[/itex], [itex]p[/itex] is non-zero when [itex]E[/itex] is non-zero. In fact,

[tex]E = cp[/tex]

for a photon.
 
i wish that i was in a higher physics class so that i could understand you.
 
3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?
The inertial mass M (aka relativistic mass) of a photon is defined just like the mass of all particles, as M/i] = p/v = p/c where p is the magnitude of the momentom and v is the particle's speed. I believe that you're thinking about a photon's proper mass m, which is zero for all photons.

The definition of the mass of a particle allows the following relation to be derived (let m = proper mass)

p = sqrt[1-(v/c)sup2]/c

This can be solved for m which in turn will be a function of the energy and momentum and when E = pc me will always turn out to be 0.

Pete
 

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