How Can Photons Have Momentum If They Have No Mass?

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3dsmax
Wikipedia says that photons have momentum. How can that be possible since p=mv?
 
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3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?


The Poynting vector,S, gives momentum of light, and is given by:

S = E X B...E= electric field
B= magnetic field
X is cross product

However, this is the classical answer...and maybe this answer should be in classical section.:smile:
 
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3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?

According to relativity, the spatial momentum of a "particle" that has rest mass [itex]m[/itex] is

[tex]p = \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}}.[/tex]

To consider a photon, let [itex]m \rightarrow 0[/itex] and [itex]v \rightarrow c.[/itex] This gives zero over zero, which is indeterminant, and can be anything (including non-zero values), depending on how the limits are taken.

Also, relaltivity says that for any particle,

[tex]E^2 - (cp)^2 = \left(mc^2\right)^2.[/tex]

Even if [itex]m=0[/itex], [itex]p[/itex] is non-zero when [itex]E[/itex] is non-zero. In fact,

[tex]E = cp[/tex]

for a photon.
 
3dsmax said:
Wikipedia says that photons have momentum. How can that be possible since p=mv?
The inertial mass M (aka relativistic mass) of a photon is defined just like the mass of all particles, as M/i] = p/v = p/c where p is the magnitude of the momentom and v is the particle's speed. I believe that you're thinking about a photon's proper mass m, which is zero for all photons.

The definition of the mass of a particle allows the following relation to be derived (let m = proper mass)

p = sqrt[1-(v/c)sup2]/c

This can be solved for m which in turn will be a function of the energy and momentum and when E = pc me will always turn out to be 0.

Pete