How can the Intermediate Value Theorem be used to find a root of a polynomial?

  • Thread starter Thread starter Dynex
  • Start date Start date
  • Tags Tags
    Value
Click For Summary
To apply the Intermediate Value Theorem (IVT) for the polynomial p(x)=60x(1+x)^72-(1+x)^72+1, one must find values of x that yield outputs less than 0 and greater than 0. The discussion highlights the importance of evaluating the polynomial at specific integer values, such as -1, which returns a positive result. Participants suggest testing integers around the suspected root to identify where the function changes sign. The challenge arises from the high degree of the polynomial, making it difficult to compute directly. Ultimately, the goal is to confirm the existence of a root between the identified values using the IVT.
Dynex
Messages
10
Reaction score
0
Hey i was jus wondering how to solve this equation i need to find a value of x when subsituted in the eqn is less than 0 so a negative value and a value of x when substituted into the eqn is greater than 0 so a positive value
this will prove that a root exists between those domains (ie. Intermediate value theorm)

p(x)=60x(1+x)^72-(1+x)^72+1

Thankz for the help
 
Physics news on Phys.org
if you're trying to test for a # greater/less than 0, just set your equation equal to 0 and solve for x. then choose values greater/less than the value you found.
 
hey yea that's wa i was plannin on doing but since its like ^72 i can't figure that part out
 
Just by staring at p(x) you can tell one root. Can you guess?
 
is it 0 -1 or 1
 
Whcih do you think?
 
hmmm ill go with -1 ?
 
Okay, plug in x = -1. What do you get?
 
"middle-term"
 
  • #10
i got a value of 1
 
  • #11
which is greater than 0 so now i need to find a value where f(x)<0
 
  • #12
any ideas?
 
  • #13
I'd try the next integers to either side.
 
  • #14
when i tried 2 , 3 and four i got really large numbers
 
  • #15
You are not paying attention to the polynomial's terms.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K