How can the vector derivative be calculated from this photo?

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The discussion focuses on calculating the vector derivative from a given photo, specifically using the relationship between radius and sine. The expression derived indicates that the change in radius, denoted as |∆r|, is approximately equal to 2r multiplied by sin(∆θ/2), which can be simplified to r|∆θ|. Additionally, the direction of ∆r is tangential, represented as ∆r = r(∆θ) θ. This establishes a clear mathematical framework for understanding vector derivatives in relation to angular changes.

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from this photo its a radius multiplied by sinus which is aproximated to its angle

and the divided by dt

32zi49h.gif




but i don't know how they got the expreesion on the top of the photo

from the graph on the photo

11jlsad.jpg
 
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shalom nhrock3! :smile:

(btw, we say sine or sin, not sinus :wink:)

|∆r| is approximately the length of the chord, which is 2r |sin(∆θ/2)|, or approximately 2r(|∆θ|/2), = r|∆θ| :wink:

and the direction of ∆r is obviously tangential, ie along θ

so ∆r = r(∆θ) θ
 

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