How can the volume of water needed to melt an iceberg be determined?

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SUMMARY

The volume of water required to melt an iceberg can be determined using the equation m_{ice}c_{ice}(0-T_{ice}) + m_{ice}L_{f} + m_{ice}c_{ice}(T_{equ}-0) = m_{ocean}c_{ocean}(T_{ocean}-T_{equ}). In this equation, m_{ice} represents the mass of the iceberg, c_{ice} is the specific heat capacity of ice, L_{f} is the latent heat of fusion, and c_{ocean} is the specific heat capacity of ocean water. The equilibrium temperature (T_{equ}) is crucial for accurate calculations, and it is assumed to be 0ºC for simplification in this discussion.

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dilasluis
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1. An iceberg of mass [tex]m_{ice}[/tex] is melted by the ocean at temperature [tex]T_{ocean}[/tex]. Knowing that the iceberg is at a temperature [tex]T_{ice}[/tex] what was the volume of water needed to melt the iceberg?



2. [tex]m_{ice}c_{ice}(0-T_{ice})+m_{ice}L_{f}+m_{ice}c_{ice}(T_{equ}-0)=m_{ocean}c_{ocean}(T_{ocean}-T_{equ})[/tex]




3. The problem is that I can't find another equation to determine the temperature of equilibrium.
 
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The volume of water needed to melt the iceberg? What's that supposed to mean? In an ideal world, every water molecule in the ocean gives an equal amount of heat to the iceberg.
 
I solved the problem considering that the equilibrium temperature is 0ºC. The iceberg is melted and it lowers the water temperature around it to 0ºC. Anyone has any idea?
 

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