How can we find out from the Lagrangian if energy is conserved?

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SUMMARY

The discussion focuses on understanding the decomposition of the Lagrangian into kinetic and potential energy and determining energy conservation in a system described by a Lagrangian. It is established that not all Lagrangians can be decomposed in this manner. A key conclusion is that if the partial derivative of the Lagrangian with respect to time is zero, a conserved quantity exists, which is often energy, but not always. The conditions for energy conservation include the potential being independent of velocity and the transformation from Cartesian to generalized coordinates being time-independent.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with Euler-Lagrange equations
  • Knowledge of kinetic and potential energy concepts
  • Basic calculus, particularly differentiation and the product rule
NEXT STEPS
  • Study the Euler-Lagrange equations in detail
  • Explore the concept of conserved quantities in Lagrangian mechanics
  • Read "Classical Dynamics" by Jose and Saletan for in-depth examples
  • Investigate the relationship between the Hamiltonian and energy conservation
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Students and professionals in physics, particularly those studying classical mechanics, as well as educators looking to deepen their understanding of Lagrangian dynamics and energy conservation principles.

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I actually have 2 questions.

1)How do you decompose the Lagrangian into kinetic and potential energy?

2)Knowing the Lagrangian, how do we find out if energy of the system is conserved.

Example: L=q'^2*sin(q)+q'*exp(q)+q

q' is the time derivative of q.

Thanks in advance
 
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(1) Not all Lagrangians can be decomposed in kinetic and potential

(2) This can be a little trickier. Sometimes you'll simply hear that if a Lagrangian does not explicity depend on time then energy is conserved but its not that simple. First of all, if [tex]\partial L/\partial t=0[/tex] then you'll have a conserved quantity. Let's see what it looks like:

[tex] \frac{dL}{dt}=\frac{\partial L}{\partial q}\dot{q}+\frac{\partial L}{\partial \dot{q}}\ddot{q}+0[/tex]

We can replace the [tex]\partial L/\partial q[/tex] using the Euler-Lagrange equations, this gives:

[tex] \frac{dL}{dt}=\dot{q}\frac{d}{dt}\frac{\partial L}{\partial \dot{q}}+\frac{\partial L}{\partial \dot{q}}\ddot{q}[/tex]

Recognize the product rule and move some terms around:

[tex] \frac{d}{dt}(\dot{q}\frac{\partial L}{\partial \dot{q}}-L)=0[/tex]

This gives us a conserved quantity which is often the energy. But not always. If you can get a hold of a copy of Classical Dyanmics by Jose and Saletan they work out the details, but the result is that the above quantity is the energy if

(1) the potential is independent of velocity
(2) the transformation from cartesian to generalized coordinates is time independent.

As for your Lagrangian, I'd be interested in knowing its motivation? Or is it just a random calculation in a textbook?
 
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Thanks for the explanation. That is the question I asked my professor. Its possible to prove that Hamiltonian is time independent (full derivative with respect to time is 0) from the fact that the partial derivative of Lagrangian is 0. But energy is not always equal to H. It was some random Lagrangian from the practice exam that I modified I little.
 

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