How Can We Geometrically Describe Vectors Orthogonal to the Vector $(-4,1,-3)$?

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SUMMARY

The discussion focuses on geometrically describing vectors orthogonal to the vector $(-4,1,-3)$. The key conclusion is that these orthogonal vectors lie in a plane defined by the equation $-4x + y - 3z = 0$, which passes through the origin. This plane is perpendicular to the given vector, illustrating the relationship between vectors and their orthogonal counterparts in three-dimensional space.

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Hey!

How could we describe geometrically the vectors that are orthogonal to the Vector $(-4,1,-3)$ ?
 
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mathmari said:
Hey!

How could we describe geometrically the vectors that are orthogonal to the Vector $(-4,1,-3)$ ?

Hey mathmari! (Smile)

It's the plane perpendicular to the vector that contains the origin.
Its equation is:
$$(x,y,z)\cdot (-4,1,-3)=0 \quad \Leftrightarrow \quad -4x+y-3z=0$$
(Mmm)
 
Thank you very much! (Mmm)
 

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